java语言程序设计(基础篇)第十版编程练习题[1.13]

(代数：求解 2 x 2 线性方程)可以使用Cramer规则解下面的 2 x 2 线性方程组：

ax + by = e		ed - bf		af - ec
x = ———————	y = ————————
cx + dy = f		ad - bc		ad - bc

编写程序，求解以下方程组并显示x和y的值。
3.4x + 50.2y = 44.5
2.1x + 0.55y = 5.9

/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package dome1_13;

/**
*
* @author Administrator
*/
public class Dome1_13 {

/**
* @param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
double x = (44.5 * 0.55 - 50.2 * 5.9) / (3.4 * 0.55 - 50.2 * 2.1);
System.out.println(x);
double y = (3.4 * 5.9 - 44.5 * 2.1) / (3.4 * 0.55 - 50.2 * 2.1);
System.out.println(y);
}

}