您的位置:首页 > 大数据 > 人工智能

IOI 2017 Practice Contest mountains

2018-09-07 10:33 543 查看

Mountains

题面

题意:

   选最多的点使得亮亮看不见。

分析:

  分治,solve(l,r)为区间[l,r]的答案。那么如果不选最高点,分治两边即可,选了最高点,那么在最高点看不见的区间里分治。

代码:

#include"mountains.h"
#include<bits/stdc++.h>
using namespace std;

const int N = 2010;
int y
;
int f

;

bool Judge(int a,int b,int c) { // a see c ?
// ((y[a] - y[b]) / (a - b)) > ((y[a] - y[c]) / (a - c));
return 1ll * (y[a] - y[b]) * (a - c) > 1ll * (y[a] - y[c]) * (a - b);
}

int solve(int l,int r) {
if (f[l][r]) return f[l][r];
if (l > r) return 0;
if (l == r) return 1;
int pos = -1, mx = -1;
for (int i=l; i<=r; ++i) if (y[i] > mx) pos = i, mx = y[i];
int ans1 = solve(l, pos - 1) + solve(pos + 1, r); // select max_height_node

int ans2 = 0; // don't select this node
for (int i=pos-1,j; i>=l; i=j) {
for (j=i-1; j>=l; --j) {  // i can see pos
if (Judge(j, i, pos)) { // j can't see pos
if (j == l) ans2 += solve(l, i - 1);
continue;
}
if (j + 1 <= i - 1) ans2 += solve(j + 1, i - 1); // this Section can't see pos
break;
}
}
for (int i=pos+1,j; i<=r; i=j) {
for (j=i+1; j<=r; ++j) {
if (Judge(pos, i, j)) {
if (j == r) ans2 += solve(i + 1, r);
continue;
}
if (i + 1 <= j - 1) ans2 += solve(i + 1, j - 1);
break;
}
}
return f[l][r] = max(ans1, ans2 + 1);
}

int maximum_deevs(vector<int> A) {
int n = A.size();
for (int i=1; i<=n; ++i) y[i] = A[i - 1];
return solve(1, n);
}

 

内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: 
相关文章推荐