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【2018Multi-University-Training Contest04】Problem C. Problems on a Tree

2018-08-02 08:08 288 查看
维护1边的联通块和2边的联通块,合并的时候直接启发式合并。

cdqz的大爷好强啊。

#include<bits/stdc++.h>
#define lson (o<<1)
#define rson (o<<1|1)
#define fi first
#define sc second
#define dbg(x) cout<<#x<<" = "<<(x)<<endl;
typedef long long ll;
typedef unsigned int uint;
typedef unsigned long long ull;
using namespace std;
const double pi=acos(-1);
const double eps=1e-6;
inline int lowbit(int x){return x&(-x);}
inline int read(){
int f=1,x=0;char ch;
do{ch=getchar();if(ch=='-')f=-1;}while(ch<'0'||ch>'9');
do{x=x*10+ch-'0';ch=getchar();}while(ch>='0'&&ch<='9');
return f*x;
}
template<typename T> inline T max(T x,T y,T z){return max(max(x,y),z);}
template<typename T> inline T min(T x,T y,T z){return min(min(x,y),z);}
template<typename T> inline T sqr(T x){return x*x;}
template<typename T> inline void checkmax(T &x,T y){x=max(x,y);}
template<typename T> inline void checkmin(T &x,T y){x=min(x,y);}
template<typename T> inline void read(T &x){
x=0;T f=1;char ch;do{ch=getchar();if(ch=='-')f=-1;}while(ch<'0'||ch>'9');
do x=x*10+ch-'0',ch=getchar();while(ch<='9'&&ch>='0');x*=f;
}
template<typename A,typename B,typename C> inline A fpow(A x,B p,C yql){
A ans=1;
for(;p;p>>=1,x=1LL*x*x%yql)if(p&1)ans=1LL*x*ans%yql;
return ans;
}
struct FastIO{
static const int S=1310720;
int wpos;char wbuf[S];
FastIO():wpos(0) {}
inline int xchar(){
static char buf[S];
static int len=0,pos=0;
if(pos==len)pos=0,len=fread(buf,1,S,stdin);
if(pos==len)return -1;
return buf[pos++];
}
inline int read(){
int c=xchar(),x=0;
while(c<=32&&~c)c=xchar();
if(c==-1)return -1;
for(;'0'<=c&&c<='9';c=xchar())x=x*10+c-'0';
return x;
}
}io;
//#define read io.read
const int N=200010;
int add
,tag2
,fa1
,fa2
,size1
,size2
,fa
,d
;
int n,m;
vector<int> G
;
inline int find(int *fa,int x){return x==fa[x]?x:fa[x]=find(fa,fa[x]);}
inline void merge2(int x,int y){
int xx=find(fa1,x),yy=find(fa1,y);
if(d[xx]<d[yy])swap(xx,yy);
add[yy]-=size2[xx];yy=find(fa2,yy);
fa2[xx]=yy;size2[yy]+=size2[xx];
add[find(fa1,fa[yy])]+=size2[xx];
}
inline void merge1(int x,int y){
int xx=find(fa1,x),yy=find(fa1,y);
if(d[xx]<d[yy])swap(xx,yy);
fa1[xx]=yy;size1[yy]+=size1[xx];
add[yy]+=add[xx];
}
inline void dfs(int u){
d[u]=d[fa[u]]+1;
add[u]=0;
for(int i=0;i<G[u].size();i++){
int v=G[u][i];
if(v==fa[u])continue;
fa[v]=u;dfs(v);add[u]++;
}
}
vector<pair<int,int> >p1,p2;
inline void clear(){
memset(add,0,sizeof(add));
for(int i=1;i<=n;i++){
fa1[i]=i;fa2[i]=i;size1[i]=1;size2[i]=1;G[i].clear();
}
p1.clear();p2.clear();
}
inline void work(){
for(int i=1;i<n;i++){
int u=read(),v=read(),w=read();
G[u].push_back(v);G[v].push_back(u);
if(w==1){
p1.push_back(make_pair(u,v));
//merge2(u,v);merge1(u,v);
}
else if(w==2)p2.push_back(make_pair(u,v));
}
dfs(1);
for(int i=0;i<p1.size();i++){
pair<int,int> p=p1[i];
merge2(p.fi,p.sc);merge1(p.fi,p.sc);
}
for(int i=0;i<p2.size();i++){
pair<int,int> p=p2[i];
merge2(p.fi,p.sc);
}
while(m--){
int u=read(),v=read(),t=read(),s=read();
u=find(fa1,u);v=find(fa1,v);
if(u!=v){
if(find(fa2,u)==find(fa2,v))merge1(u,v);
else merge2(u,v);
}
s=find(fa1,s);t=find(fa1,t);int flag=0;
if(find(fa2,s)==find(fa2,t))printf("1 "),flag=1;
else{
if(d[find(fa2,s)]>d[find(fa2,t)]){
if(find(fa1,fa[find(fa2,s)])==t)printf("1 "),flag=1;
}
else if((t==find(fa2,t)&&find(fa2,fa[t])==find(fa2,s)))printf("1 "),flag=1;
}
if(!flag)printf("0 ");
printf("%d\n",size2[find(fa2,t)]+add[t]+(t==find(fa2,t)?size2[find(fa2,fa[t])]:0));
}
}
int main(){
int T=read();
while(T--){
n=read();m=read();
clear();
work();
}
}
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