LeetCode第一题(Two Sum)
2018-03-31 17:14
399 查看
Two Sum
Given an array of integers, return indices of the two numbers such that they add up to a specific target.You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1].
python代码如下
class Solution: def twoSum(self, nums, target): """ :type nums: List[int] :type target: int :rtype: List[int] """ r = [] for i in range(len(nums)): for j in range(i+1, len(nums)): if nums[i] + nums[j] == target: r.append(i) r.append(j) return r
相关文章推荐
- Leetcode 第一题(Two Sum)
- leetcode第一题(TWO SUM)
- Leetcode 第一题 Two Sum java代码
- LeetCode第一关:Two Sum --> Difficulty: Easy
- leetcode 第一题:two sum
- Leetcode第一题<two sum>
- LeetCode 1.Two Sum ------------LeetCode 第一题
- leetcode第一题twoSum
- leetcode中第一题twosum问题解答算法的可行性证明
- [leetcode]leetcode第一题 1. Two Sum java O(n)解法
- LeetCode刷题之第一题——Add Two Numbers
- [leetcode]Two Sum
- LeetCode 1.Two Sum 解题报告
- LeetCode:: Two Sum 详细分析
- #leetcode#Sum of Two Integers
- [leetcode 167] Two Sum II - Input array is sorted
- [LeetCode]712. Minimum ASCII Delete Sum for Two Strings
- 【LeetCode】1. Two Sum 解题报告
- leetcode Two Sum
- leetcode 1.Twosum python