02_checkio_House_Passworld

Stephan and Sophia forget about security and use simple passwords for everything. Help Nikola develop a password security check module. The password will be considered strong enough if its length is greater than or equal to 10 symbols, it has at least one digit, as well as containing one uppercase letter and one lowercase letter in it. The password contains only ASCII latin letters or digits.Input: A password as a string.Output: Is the password safe or not as a boolean or any data type that can be converted and processed as a boolean. In the results you will see the converted results.Example:checkio('A1213pokl') == False
checkio('bAse730onE') == True
checkio('asasasasasasasaas') == False
checkio('QWERTYqwerty') == False
checkio('123456123456') == False
checkio('QwErTy911poqqqq') == True

def checkio(data):

#replace this for solution
return True or False

#Some hints
#Just check all conditions

if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

代码：def checkio(data):
if len(data)>9:
if any(i.isupper() for i in data) and any(i.islower() for i in data) and any(i.isdigit() for i in data):
return True
else:
return False
else:
return False其它人的代码：checkio = lambda s: not(
len(s) < 10
or s.isdigit()
or s.isalpha()
or s.islower()
or s.isupper()
)

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"

import re

DIGIT_RE = re.compile('\d')
UPPER_CASE_RE = re.compile('[A-Z]')
LOWER_CASE_RE = re.compile('[a-z]')

def checkio(data):
"""
Return True if password strong and False if not

A password is strong if it contains at least 10 symbols,
and one digit, one upper case and one lower case letter.
"""
if len(data) < 10:
return False

if not DIGIT_RE.search(data):
return False

if not UPPER_CASE_RE.search(data):
return False

if not LOWER_CASE_RE.search(data):
return False

return True

if __name__ == '__main__':
assert checkio('A1213pokl')==False, 'First'
assert checkio('bAse730onE4')==True, 'Second'
assert checkio('asasasasasasasaas')==False, 'Third'
assert checkio('QWERTYqwerty')==False, 'Fourth'
assert checkio('123456123456')==False, 'Fifth'
assert checkio('QwErTy911poqqqq')==True, 'Sixth'
print('All ok')

import re
def checkio(data):
return True if re.search("^(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).*$", data) and len(data) >= 10 else False

if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"

def checkio(data):
import re
if len(data)<10:
return False
if not re.search('[0-9]', data):
return False
if not re.search('[a-z]', data):
return False
if not re.search('[A-Z]', data):
return False
return True

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"

def checkio(data):
if len(data) < 10:
return False
if data.upper() == data:
return False
if data.lower() == data:
return False
return any(c.isdigit() for c in data)

#Some hints
#Just check all conditions

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"

any() 函数的用法，以及与all()函数的区别，原文地址：https://www.cnblogs.com/nulige/p/6128816.html
any()与all()函数的区别:　　any是任意，而all是全部。  版本：该函数适用于2.5以上版本，兼容python3.x版本。 any(...)    any(iterable) -> bool        Return True if bool(x) is True for any x in the iterable.    If the iterable is empty, return False. any(iterable)说明：参数iterable：可迭代对象；如果当iterable所有的值都是0、''或False时，那么结果为False，如果所有元素中有一个值非0、''或False，那么结果就为True函数等价于：

1 def any(iterable):
2
3    for element in iterable:
4
5        if  element:
6
7            return False
8
9    return True

 示例：

1 >>> any(['a', 'b', 'c', 'd'])  #列表list，元素都不为空或0
2 True
3
4 >>> any(['a', 'b', '', 'd'])  #列表list，存在一个为空的元素
5 True
6
7 >>> any([0, '', False])  #列表list,元素全为0,'',false
8 False
9
10 >>> any(('a', 'b', 'c', 'd'))  #元组tuple，元素都不为空或0
11 True
12
13 >>> any(('a', 'b', '', 'd'))  #元组tuple，存在一个为空的元素
14 True
15
16 >>> any((0, '', False))  #元组tuple，元素全为0,'',false
17 False
18
19 >>> any([]) # 空列表
20 False
21
22 >>> any(()) # 空元组
23 False

 all(...)    all(iterable) -> bool        Return True if bool(x) is True for all values x in the iterable.    If the iterable is empty, return True. 如果iterable的所有元素不为0、''、False或者iterable为空，all(iterable)返回True，否则返回False；函数等价于：

1 def all(iterable):
2
3     for element in iterable:
4         if not element:
5             return False
6     return True

 示例：

1 >>> all(['a', 'b', 'c', 'd'])  #列表list，元素都不为空或0
2 True
3 >>> all(['a', 'b', '', 'd'])  #列表list，存在一个为空的元素
4 False
5 >>> all([0, 1，2, 3])  #列表list，存在一个为0的元素
6 False
7
8 >>> all(('a', 'b', 'c', 'd'))  #元组tuple，元素都不为空或0
9 True
10 >>> all(('a', 'b', '', 'd'))  #元组tuple，存在一个为空的元素
11 False
12 >>> all((0, 1，2, 3))  #元组tuple，存在一个为0的元素
13 False
14
15 >>> all([]) # 空列表
16 True
17 >>> all(()) # 空元组
18 True

注意：空元组、空列表返回值为True，这里要特别注意。