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HackerRank - maximum-perimeter-triangle 【水】

2018-03-11 21:53 435 查看




题意

给出一系列数字,判断其中哪三个数字可以构成一个三角形,如果有多个,输出周长最大的那个,如果没有输出 - 1

思路

数据较小,所有情况FOR一遍 判断一下

AC代码

#include <cstdio>
#include <cstring>
#include <ctype.h>
#include <cstdlib>
#include <iostream>
#include <algorithm>
#include <cmath>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <map>
#include <stack>
#include <set>
#include <numeric>
#include <sstream>

using namespace std;
typedef long long LL;

const double PI  = 3.14159265358979323846264338327;
const double E   = 2.718281828459;
const double eps = 1e-6;

const int MAXN = 0x3f3f3f3f;
const int MINN = 0xc0c0c0c0;
const int maxn = 50 + 5;
const int MOD  = 1e9 + 7;

LL a[maxn];

bool judge(LL b[])
{
if (b[0] + b[1] > b[2])
return true;
return false;
}

int main()
{
int n;
cin >> n;
LL b[3], ans[3];
LL MAX = MINN;
for (int i = 0; i < n; i++)
scanf("%lld", &a[i]);
sort(a, a + n);
int i, j, k;
for (i = 0; i < n; i++)
{
for(j = i + 1; j < n; j++)
{
for (k = j + 1; k < n; k++)
{
b[0] = a[i];
b[1] = a[j];
b[2] = a[k];
sort(b, b + 3);
if (judge(b))
{
LL temp = b[0] + b[1] + b[2];
if (temp > MAX)
{
for (int l = 0; l < 3; l++)
ans[l] = b[l];
MAX = temp;
}
}
}
}
}
if (MAX != MINN)
{
printf("%lld %lld %lld\n", ans[0], ans[1], ans[2]);
}
else
cout << -1 << endl;
}
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