Linux_C练习: 通过编程实现,统计1~n有多少个9

#include<stdio.h>
int n;

int main()
{
int i;
int count = 0;
int temp1, temp2;
printf("please input number!\n");
scanf("%d", &n);
for(i = 1; i < n; ++i)
{
temp1 = i;
while(temp1 != 0)
{
temp2 = temp1 % 10;
temp1 = temp1 / 10;
if(temp2 == 9)
{
count += 1;
}
}
}
printf("Total is %d\n",count);
return 0;
}