您的位置:首页 > 其它

PAT 天梯赛 L1-023. 输出GPLT 【水】

2018-03-08 14:43 429 查看
题目链接

https://www.patest.cn/contests/gplt/L1-023

AC代码

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <cstring>
#include <map>
#include <stack>
#include <set>
#include <cstdlib>
#include <ctype.h>
#include <numeric>
#include <sstream>
using namespace std;

typedef long long LL;
const double PI = 3.14159265358979323846264338327;
const double E = 2.718281828459;
const double eps = 1e-6;
const int MAXN = 0x3f3f3f3f;
const int MINN = 0xc0c0c0c0;
const int maxn = 1e5 + 5;
const int MOD = 1e9 + 7;

int main()
{
string s;
cin >> s;
int len = s.size();
int i;
int a[4] = {0};
for (i = 0; i < len; i++)
{
if (s[i] == 'G' || s[i] == 'g')
a[0]++;
else if (s[i] == 'P' || s[i] == 'p')
a[1]++;
else if (s[i] == 'L' || s[i] == 'l')
a[2]++;
else if (s[i] == 'T' || s[i] == 't')
a[3]++;
}
while (a[0] || a[1] || a[2] || a[3])
{
if (a[0])
{
printf("G");
a[0]--;
}
if (a[1])
{
printf("P");
a[1]--;
}
if (a[2])
{
printf("L");
a[2]--;
}
if (a[3])
{
printf("T");
a[3]--;

b125
}
}
cout << endl;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: