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Queue at the School

2018-03-04 23:01 447 查看
During the break the schoolchildren, boys and girls, formed a queue of n people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling awkward for standing in front of the girls in the queue and they started letting the girls move forward each second.
Let's describe the process more precisely. Let's say that the positions in the queue are sequentially numbered by integers from 1 to n, at that the person in the position number 1 is served first. Then, if at time x a boy stands on the i-th position and a girl stands on the (i + 1)-th position, then at time x + 1 the i-th position will have a girl and the (i + 1)-th position will have a boy. The time is given in seconds.
You've got the initial position of the children, at the initial moment of time. Determine the way the queue is going to look after t seconds.
InputThe first line contains two integers n and t (1 ≤ n, t ≤ 50), which represent the number of children in the queue and the time after which the queue will transform into the arrangement you need to find.
The next line contains string s, which represents the schoolchildren's initial arrangement. If the i-th position in the queue contains a boy, then the i-th character of string s equals "B", otherwise the i-th character equals "G".
OutputPrint string a, which describes the arrangement after t seconds. If the i-th position has a boy after the needed time, then the i-th character a must equal "B", otherwise it must equal "G".
ExampleInput
5 1
BGGBG
Output
GBGGB
Input
5 2
BGGBG
Output
GGBGB
Input
4 1
GGGB
OutputGGGB题意:输入n(学生人数),t(时间),每秒切换一次位置,为了体现女士优先的绅士风格,站在队列靠前的男生与紧邻靠后的女生交换一次位置,每秒交换一次,求t 秒后,队列分布情况。题解:两层循环,外层为时间 t ,内层为 遍历队列,若满足条件则交换位置。Select Code
#include<stdio.h>
int main()
{
int i,j,n,t;
char x[60];
scanf("%d %d",&n,&t);
getchar();
gets(x);
while(t)
{
for(i=0;i<n;i++)
{
if(x[i]=='B'&&x[i+1]=='G')
{
j=x[i];
x[i]=x[i+1];
x[i+1]=j;
i=i+1;
}
}
t--;
}
puts(x);
return 0;
}
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