leetcode 1 Two Sum
2018-03-04 22:36
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1 | Two Sum | 37.00% | 查找数组中相加等于给定数字的两个元素 |
#!/usr/bin/env python3 # -*- coding: utf-8 -*- """ Created on Sun Dec 24 13:56:44 2017 @author: vicky """ #1. Two Sum class Solution: def twoSum(self, nums, target): """ :type nums: List[int] :type target: int :rtype: List[int] """ a=list([0,0]) for i in range(len(nums)): for j in range(i+1,len(nums)): if nums[i]+nums[j]==target: a=[i,j] break return(a) #class Solution: # def twoSum(self, nums, target): # """ # :type nums: List[int] # :type target: int # :rtype: List[int] # """ # b={} #指针 # for i in range(len(nums)): # b[nums[i]]=i # print(b) # #for i in range(len(nums)): # if (target-nums[i] in b):# and i<len(nums) and (target-nums[i]!=nums[i]): # print([b[target-nums[i-1]],i]) # return([b[target-nums[i]]],i) class Solution: def twoSum(self, nums, target): """ :type nums: List[int] :type target: int :rtype: List[int] """ b={} #指针 for i in range(len(nums)): if target-nums[i] in b: #print([b[target-nums[i]],i]) return([b[target-nums[i]],i]) b[nums[i]]=i #print(b) class Solution: def twoSum(self, nums, target): """ :type nums: List[int] :type target: int :rtype: List[int] """ b={} #指针 for i in range(len(nums)): if target-nums[i] in b: #print([b[target-nums[i]],i]) return([b[target-nums[i]],i]) b[nums[i]]=i #print(b) def stringToIntegerList(input): return json.loads(input) def integerListToString(nums, len_of_list=None): if not len_of_list: len_of_list = len(nums) return json.dumps(nums[:len_of_list]) def main(): import sys def readlines(): for line in sys.stdin: yield line.strip('\n') lines = readlines() while True: try: line = lines.__next__() nums = stringToIntegerList(line); line = lines.__next__() target = int(line); ret = Solution().twoSum(nums, target) out = integerListToString(ret); print(out) except StopIteration: break if __name__ == '__main__': main()
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