2017年复试程序设计题

2017年

题目

格式转换，从一个文件中读取日期07/21/2016，转换为以下格式July 21,2016并输出到屏幕上

方法一：

#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
using namespace std;

int main(){

ifstream is("/Users/.../MyDate.txt");

if (!is){
cerr << "File cannot be opened!" << endl;
exit(EXIT_FAILURE);
}

string myMonth[13] = {"","Jan","Feb","Mar","Apr","May","June","July","Aug","Sept","Oct","Nov","Dec"};
string  line;
int month;
int day;
int year;

while (is >> line) {
month = stoi(line.substr(0,2));
day = stoi(line.substr(3,2));
year = stoi(line.substr(6,4));

cout << setw(4) << left  << setfill(' ') << myMonth[month] << " ";
cout << setw(2) << right << setfill('0') << day << "," << year << endl;
}

return 0;
}

运行结果：



值得注意的是，setfill(‘0’)函数设置填充字符过后是会一直生效的，所以要在输出月份之前添加一句setfill(’ ‘)以保证格式统一。

方法二：

当然也可以这么玩：

#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
using namespace std;

int main(){

ifstream is("/Users/.../MyDate.txt");
if (!is) {
cerr << "File cannot be opened!" << endl;
exit(EXIT_FAILURE);
}

string temp;
string mon[13] = {"","Jan","Feb","Mar","Apr","May","June","July","Aug","Sept","Oct","Nov","Dec"};
int month,day,year;
size_t Pos_1,Pos_2;

while (is >> temp) {
Pos_1 = temp.find("/");
Pos_2 = temp.find_last_of("/");

month = stoi(temp.substr(0,Pos_1));
day = stoi(temp.substr(Pos_1 + 1,Pos_2 - Pos_1 - 1));
year = stoi(temp.substr(Pos_2 + 1));

cout << setw(4) << left << setfill(' ') << mon[month] << " " << setw(2) << right << setfill('0') << day << "," << year << endl;
}

return 0;
}

法二更加通用化。