LeetCode400. Nth Digit
2018-03-01 20:23
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题目
Find the nth digit of the infinite integer sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, …Note:
n is positive and will fit within the range of a 32-bit signed integer.
Example 1:
Input: 3 Output: 3
Example 2:
Input: 11 Output: 0 Explanation: The 11th digit of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ... is a 0, which is part of the number 10.
答案
public int findNthDigit(int n) { int len = 1, start = 1; long count = 9; while (n > len * count) { n -= len * count; len++; count *= 10; start *= 10; } // (n - 1) 的理解很关键,如果是 n ,则在正好 n == len 的情况下会多出去一位 start += (n - 1) / len; //这里 (n - 1) 减的那一位正好和 charAt() 从 0 开始多的那一位抵消 return String.valueOf(start).charAt((n - 1) % len) - '0'; }
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