LeetCode之771:Jewels and Stones
2018-02-28 13:51
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1. 解法1
(遍历比较,时间复杂度O(J*S),空间复杂度O(1))1.1 C#代码
public class Solution { public int NumJewelsInStones(string J, string S) { int Jlen = J.Length; int Slen = S.Length; int count = 0; for(int i=0; i<Jlen;i++) { for(int j=0;j<Slen;j++) { if(S[j] == J[i]) ++count; } } return count; } }
1.2 Python3 代码
class Solution: def numJewelsInStones(self, J, S): """ :type J: str :type S: str :rtype: int """ count = 0 for j in J: for s in S: if j == s: count += 1 return count
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