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POJ 3469 Dual Core CPU——最小割最大流

2018-02-18 12:01 501 查看
while ((f = dfs(s, t, INF)) > 0) flow += f;模板里这个地方推荐加一个括号,不然有的编译器会有问题

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
using namespace std;
const int maxn = 20005;
const int INF = 0x3f3f3f3f;
struct Edge {
int to, cap, rev;
Edge(int x=0, int y=0, int z=0) : to(x), cap(y), rev(z) {}
};
vector<Edge> G[maxn];
int level[maxn], iter[maxn];
void addedge(int u, int v, int cap) {
G[u].push_back(Edge(v, cap, G[v].size()));
G[v].push_back(Edge(u, 0, G[u].size()-1));
}
void bfs(int s) {
memset(level, -1, sizeof(level));
queue<int> q;
level[s] = 0;
q.push(s);
while (!q.empty()) {
int v = q.front(); q.pop();
for (int i = 0; i < G[v].size(); i++) {
Edge &e = G[v][i];
if (e.cap > 0 && level[e.to] < 0) {
level[e.to] = level[v] + 1;
q.push(e.to);
}
}
}
}
int dfs(int v, int t, int f) {
if (v == t) return f;
for (int &i = iter[v]; i < G[v].size(); i++) {
Edge &e = G[v][i];
if (e.cap > 0 && level[v] < level[e.to]) {
int d = dfs(e.to, t, min(f, e.cap));
if (d > 0) {
e.cap -= d;
G[e.to][e.rev].cap += d;
return d;
}
}
}
return 0;
}
int max_flow(int s, int t) {
int flow = 0;
while (true) {
bfs(s);
if (level[t] < 0) return flow;
memset(iter, 0, sizeof(iter));
int f;
while ((f = dfs(s, t, INF)) > 0) flow += f;
}
}
int n, m;
int main() {
scanf("%d %d", &n, &m);
int a, b, cost;
int s = n, t = n+1;
for (int i = 0; i < n; i++) {
scanf("%d %d", &a, &b);
addedge(i, t, a);
addedge(s, i, b);
}
for (int i = 0; i < m; i++) {
scanf("%d %d %d", &a, &b, &cost);
addedge(a-1, b-1, cost);
addedge(b-1, a-1, cost);
}
printf("%d\n", max_flow(s, t));
return 0;
}
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