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121. Best Time to Buy and Sell Stock

2018-02-09 16:44 267 查看
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为求最大子序列和问题 53题

nums[i] = prices[i]-prices[i-1]

nums[0] = 0;

#include <cstdio>
#include <iostream>
#include <set>
#include <vector>
using namespace std;

int maxProfit(vector<int>& prices) {
int sum = 0;
int maxsum = 0;
for (int i=1;i<prices.size();++i)
{
if (sum  > 0)
sum += prices[i]-prices[i-1];
else
sum = prices[i]-prices[i-1];
if (sum >maxsum)
maxsum = sum;
}
return maxsum;

}
int main()
{
vector<int> a;
int x;
for(int i=0;i<6;i++)
{
cin>>x;
a.push_back(x);
}
/*int val;
cin>>val;
/*for ( int ix = 0; ix < a.size(); ++ix )
cout << a[ ix ] <<endl;*/
cout<<maxProfit(a)<<endl;
return 0 ;
}
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