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Filya and Homework CodeForces - 714B

2018-02-04 20:39 1401 查看
Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.

Filya is given an array of non-negative integers a1, a2, ..., an. First, he pick an integerx
and then he adds x to some elements of the array (no more than once), subtract
x from some other elements (also, no more than once) and do no change other elements. He wants all elements of the array to be equal.

Now he wonders if it's possible to pick such integer x and change some elements of the array using thisx in order to make all elements equal.

Input

The first line of the input contains an integer n (1 ≤ n ≤ 100 000) — the number of integers in the Filya's array. The second line containsn
integers a1, a2, ..., an (0 ≤ ai ≤ 109) —
elements of the array.

Output

If it's impossible to make all elements of the array equal using the process given in the problem statement, then print "NO" (without quotes) in the only line of the output. Otherwise print "YES"
(without quotes).

Example

Input
5
1 3 3 2 1


Output
YES


Input
5
1 2 3 4 5


Output
NO


Note

In the first sample Filya should select x = 1, then add it to the first and the last elements of the array and subtract from the second and the third elements.

点我!!!!
unique()去重函数运用
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
const int N = 100005;
int arr
;
int main(){
int n;
scanf("%d",&n);
for(int i=0;i<n;i++)
scanf("%d",&arr[i]);
sort(arr,arr+n);
int type=unique(arr,arr+n)-arr;
if(type<3||type==3&&arr[1]-arr[0]==arr[2]-arr[1])
printf("YES\n");
else printf("NO\n");
return 0;
}
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