1058. A+B in Hogwarts (20)
2018-01-29 22:53
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If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to
compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
Sample Output:
compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
简析:极简单,10分钟内包括题目和代码都可以搞定。
#include <iostream> using namespace std; int main(int argc, const char * argv[]) { int a1, b1, c1, a2, b2, c2, a, b, c; scanf("%d.%d.%d", &a1, &b1, &c1); scanf("%d.%d.%d", &a2, &b2, &c2); b1 += (c1 + c2) / 29; c = (c1 + c2) % 29; a1 += (b1 + b2) / 17; b = (b1 + b2) % 17; a = a1 + a2; printf("%d.%d.%d\n", a, b, c); return 0; }
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