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19. Remove Nth Node From End of List

2018-01-21 15:24 357 查看

19. Remove Nth Node From End of List

题目

Given a linked list, remove the nth node from the end of list and return its head.

For example,

Given linked list: 1->2->3->4->5, and n = 2.

After removing the second node from the end, the linked list becomes 1->2->3->5.

Note:
Given n will always be valid.
Try to do this in one pass.

解析

两种思路

思路一:第一遍遍历得到链表的长度,第二遍走cnt-n步,注意边界条件

思路二:两个指针,第一个先走n-1步,然后两个指针一起走

// 19. Remove Nth Node From End of List
class Solution {
public:
ListNode* removeNthFromEnd(ListNode* head, int n) {

ListNode* cur = head;
if (head==NULL)
{
return NULL;
}
int cnt = 0;
while (cur!=NULL)
{
cnt++;
cur = cur->next;
}
cur = head;
int pos = cnt - n+1;
if (pos==1)
{
return cur->next;
}
pos = pos - 2;
while (pos)
{
cur = cur->next;
pos--;
}
ListNode* dete = cur->next;
if (dete->next)
{
cur->next = cur->next->next;
}
else
{
cur->next = NULL;
}

//delete dete;
return head;
}
};

题目来源

19. Remove Nth Node From End of List
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