1034. 有理数四则运算(20)-浙大PAT乙级真题java实现

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1034. 有理数四则运算(20)

本题要求编写程序，计算2个有理数的和、差、积、商。

输入格式：

输入在一行中按照“a1/b1 a2/b2”的格式给出两个分数形式的有理数，其中分子和分母全是整型范围内的整数，负号只可能出现在分子前，分母不为0。

输出格式：

分别在4行中按照“有理数1 运算符 有理数2 = 结果”的格式顺序输出2个有理数的和、差、积、商。注意输出的每个有理数必须是该有理数的最简形式“k a/b”，其中k是整数部分，a/b是最简分数部分；若为负数，则须加括号；若除法分母为0，则输出“Inf”。题目保证正确的输出中没有超过整型范围的整数。

输入样例1：

2/3 -4/2

输出样例1：

2/3 + (-2) = (-1 1/3)

2/3 – (-2) = 2 2/3

2/3 * (-2) = (-1 1/3)

2/3 / (-2) = (-1/3)

输入样例2：

5/3 0/6

输出样例2：

1 2/3 + 0 = 1 2/3

1 2/3 – 0 = 1 2/3

1 2/3 * 0 = 0

1 2/3 / 0 = Inf

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String[] input = in.nextLine().split("[\\s/]");
in.close();
long a1 = Integer.parseInt(input[0]);
long b1 = Integer.parseInt(input[1]);
long a2 = Integer.parseInt(input[2]);
long b2 = Integer.parseInt(input[3]);

if (b1 != 0 && b2 != 0) {
add(a1, b1, a2, b2);
minus(a1, b1, a2, b2);
mutilply(a1, b1, a2, b2);
divide(a1, b1, a2, b2);
}
}
public static void tackle(long a, long b) {
if (a == 0) {

a1bc
System.out.print(0);
return;
}
boolean isMinus = a > 0 ? false : true;
if (isMinus) {
System.out.print("(-");
a = -a;
}
long gcd = getGcd(a, b);
a = a / gcd;
b = b / gcd;
if (a % b == 0) {
System.out.print(a / b);
} else if (Math.abs(a) > b) {
System.out.print(a / b + " " + (a % b) + "/" + b);
} else if (a == b) {
System.out.print(1);
} else {
System.out.print(a + "/" + b);
}
if (isMinus) {
System.out.print(")");
}
}
public static void divide(long a1, long b1, long a2, long b2) {
tackle(a1, b1);
System.out.print(" / ");
tackle(a2, b2);
System.out.print(" = ");
if (a2 == 0) {
System.out.print("Inf");
} else if (a2 < 0) {
tackle(-1 * a1 * b2, -1 * a2 * b1);
} else {
tackle(a1 * b2, a2 * b1);
}
}
public static void mutilply(long a1, long b1, long a2, long b2) {
tackle(a1, b1);
System.out.print(" * ");
tackle(a2, b2);
System.out.print(" = ");
tackle(a1 * a2, b1 * b2);
System.out.println();
}
public static void minus(long a1, long b1, long a2, long b2) {
tackle(a1, b1);
System.out.print(" - ");
tackle(a2, b2);
System.out.print(" = ");
tackle(a1 * b2 - a2 * b1, b1 * b2);
System.out.println();
}
public static void add(long a1, long b1, long a2, long b2) {
tackle(a1, b1);
System.out.print(" + ");
tackle(a2, b2);
System.out.print(" = ");
tackle(a1 * b2 + a2 * b1, b1 * b2);
System.out.println();
}
public static long getGcd(long a, long b) {
while (a % b != 0) {
long temp = a % b;
a = b;
b = temp;
}
return b;
}
}