您的位置:首页 > 其它

[luoguP1110] [ZJOI2007]报表统计(set暴力)

2018-01-16 20:13 218 查看

传送门

 

两个multiset

一个记录相邻元素的差,一个放所有的元素

2个数组

val[i]记录第i个的值,last[i]记录第i个最后插入的数的值

然后乱搞

#include <set>
#include <cstdio>
#include <iostream>
#define N 1001000
#define abs(x) ((x) < 0 ? -(x) : (x))
#define min(x, y) ((x) < (y) ? (x) : (y))
#define max(x, y) ((x) > (y) ? (x) : (y))

using namespace std;

int n, m, ans = 1e9;
int val
, last
;
multiset <int> s, ss;
multiset <int> :: iterator it;

inline int read()
{
int x = 0, f = 1;
char ch = getchar();
for(; !isdigit(ch); ch = getchar()) if(ch == '-') f = -1;
for(; isdigit(ch); ch = getchar()) x = (x << 1) + (x << 3) + ch - '0';
return x * f;
}

inline void set_insert(int x)
{
s.insert(x);
it = s.lower_bound(x);
if(it != s.begin())
it--, ans = min(ans, abs(*it - x)), it++;
if((++it) != s.end()) ans = min(ans, abs(*it - x));
}

inline void insert(int x, int y)
{
if(x != n)
ss.erase(ss.lower_bound(abs(last[x] - val[x + 1])));
ss.insert(abs(last[x] - y));
if(x != n) ss.insert(abs(val[x + 1] - y));
last[x] = y;
set_insert(y);
}

int main()
{
int i, x, y;
char s[21];
n = read();
m = read();
for(i = 1; i <= n; i++)
{
last[i] = val[i] = read();
set_insert(val[i]);
if(i > 1) ss.insert(abs(val[i] - val[i - 1]));
}
for(i = 1; i <= m; i++)
{
scanf("%s", s);
if(s[4] == 'R')
{
x = read();
y = read();
insert(x, y);
}
if(s[4] == 'G') printf("%d\n", *ss.begin());
if(s[4] == 'S') printf("%d\n", ans);
}
return 0;
}

  

内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: