python字符串反转的集中方法

string = '12345'

def string_reverse1(string):
return string[::-1]

def string_reverse2(string):
t = list(string)
l = len(t)
for i,j in zip(range(l-1, 0, -1), range(l//2)):
t[i], t[j] = t[j], t[i]
return "".join(t)

def string_reverse3(string):
if len(string) <= 1:
return string
return string_reverse3(string[1:]) + string[0]

from collections import deque
def string_reverse4(string):
d = deque()
d.extendleft(string)
return ''.join(d)

def string_reverse5(string):
#return ''.join(string[len(string) - i] for i in range(1, len(string)+1))
return ''.join(string[i] for i in range(len(string)-1, -1, -1))

print(string_reverse1(string))
print(string_reverse2(string))
print(string_reverse3(string))
print(string_reverse4(string))
print(string_reverse5(string))