复杂的指针获取字符串里的内容放入数组

#define  _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

/*
4. 有一个字符串符合以下特征 "abcdef,acccd,eeee,aaaa,e3eeee,ssss,"
a) 以逗号,隔开字串，字串数量不会超过10个，每个字串长度不会超过30
b) 以逗号分隔字符串，并把结果传出
c)参考库函数：strchr(), strncpy(), strcpy(), strlen()
*/

char ** getMem(int n)
{
char **p = malloc(n * sizeof(char *)); //char *p[]
if (p == NULL)
{
return NULL;
}

//每个元素的空间
int i = 0;
for (i = 0; i < n; i++)
{
p[i] = malloc(30 * sizeof(char)); //char a[30]
if (p[i] == NULL)
{
return NULL;
}
}

return p;

}

void getMemFree(char ***buf, int n)
{
if (buf == NULL)
{
return;
}

char **tmp = *buf;
int i = 0;

for (i = 0; i < n; i++)
{
if (tmp[i] != NULL)
{
free(tmp[i]);
tmp[i] = NULL;
}
}

free(tmp);
*buf = NULL;

}

/*
功能：把 "abcdef,acccd,eeee,aaaa,e3eeee,ssss,"，以","分隔出字符串，分配放在二维数组buf中
参数：
str：	原字符串，"abcdef,acccd,eeee,aaaa,e3eeee,ssss,"
c：	 	分隔标志：','
buf: 	指针数组首元素地址，其空间在主调函数分配
count：保存buf字符串的个数
返回值：
成功：0
失败：非0
*/
int spitString(const char *str, char c, char **buf, int *count)
{
if (str == NULL || count == NULL)
{
return -1;
}

const char *start = str;
char *p = NULL;
int i = 0; //第几行

do
{
//"abcdef,acccd,eeee,aaaa,e3eeee,ssss,"
p = strchr(start, c);
if (p != NULL)
{
int len = p - start;
if (len > 0)
{
strncpy(buf[i], start, len);
//添加结束符
*( *(buf+i) + len ) = '\0';

i++;
}
start = p + 1;
}
else
{
strcpy(buf[i], start);
i++;
break;
}

} while (*start != 0);

*count = i; //有多少行字符串

return 0;
}

int main()
{
char *p = "abcdef,acccd,eeee,aaaa,e3eeee,ssss,";
char **buf = getMem(10); //动态打造指针数组
int n = 0;
int ret = 0;

ret = spitString(p, ',', buf, &n);
if (ret != 0)
{
return ret;
}

int i = 0;
for (i = 0; i < n; i++)
{
printf("%s\n", buf[i]); //打印字符串
}

getMemFree(&buf, n); //释放空间

printf("\n");
system("pause");
return 0;
}