Leetcode 108. Convert Sorted Array to Binary Search Tree
2018-01-11 10:00
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<c>
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* sortedArrayToBST(vector<int>& nums) {
return reSolve(nums.begin(), nums.end());
}
private:
TreeNode* reSolve(auto b, auto e) {
if (b == e) return nullptr;
auto it = b + (e - b) / 2;
TreeNode* r = new TreeNode(*it);
r->left = reSolve(b, it);
r->right = reSolve(it + 1, e);
return r;
}
};
<c>
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* sortedArrayToBST(vector<int>& nums) {
return reSolve(nums.begin(), nums.end());
}
private:
TreeNode* reSolve(auto b, auto e) {
if (b == e) return nullptr;
auto it = b + (e - b) / 2;
TreeNode* r = new TreeNode(*it);
r->left = reSolve(b, it);
r->right = reSolve(it + 1, e);
return r;
}
};
<c>
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