您的位置:首页 > 其它

【转载】usr/bin/ld: cannot find -l<nameOfTheLibrary>

2018-01-02 18:51 609 查看
此文章转自
stackoverflow 中关于问题


cpp:
usr/bin/ld: cannot find -l<nameOfTheLibrary>

原地址:https://stackoverflow.com/questions/30600978/cpp-usr-bin-ld-cannot-find-lnameofthelibrary
编译过程讲的很详细,写的太好了,醍醐灌顶!

Briefly:

ld
 does
not know about where your project libs are located. You have to place it into ld's known directories or specify the full path of your library by 
-L
 parameter
to the linker. 

To be able to build your program you need to have your library in 
/bin/ld
 search
paths and your colleague too. Why? See detailed answer.

Detailed:

At first we should understand what tools do what:

The compiler produces simple 
object
files
 with unresolved symbols (it does not care about symbols so much at it's running time).

The linker combines a number of 
object
 and 
archive
files
, relocates their data and ties up symbol references into a single file: an executable or a library.

Let's start with some example. For example, you have a project which consists of 3 files: 
main.c
func.h
 and 
func.c
.

main.c
#include "func.h"
int main() {
func();
return 0;
}


func.h
void func();


func.c
#include "func.h"
void func() { }


So, when you compile your source code (
main.c
)
into an object file (
main.o
)
it can't be run yet because it has unresolved symbols. Let's start from the beginning of 
producing
an executable
workflow (without details):

The preprocessor after it's job produces the following 
main.c.preprocessed
:
void func();
int main() {
func();
return 0;
}


and the following 
func.c.preprocessed
:
void func();
void func() { }


As you may see in 
main.c.preprocessed
,
there are no connections to your 
func.c
 file
and to the 
void
func()
's implementation, compiler simply does not know about it, it compiles all the source files separately. So, to be able to compile this project you have to compile both source files by using something like like 
cc
-c main.c -o main.o
 and 
cc
-c func.c -o func.o
, this will produce 2 object files, 
main.o
 and 
func.o
func.o
 has
all it's symbols resolved because it has only one function which body is written right inside the 
func.c
 but 
main.o
 does
not have 
func
symbol
resolved yet because it does not know where it is implemented.

Let's look what is inside 
func.o
:
$ nm func.o
0000000000000000 T func


Simply, it contains a symbol which is in text code section so this is our 
func
 function.

And let's look what is inside 
main.o
:
$ nm main.o
U func
0000000000000000 T main


Our 
main.o
 has
an implemented and resolved static function 
main
 and
we are able to see it in the object file. But we also see 
func
 symbol
which marked as unresolved 
U
,
and thus we are unable to see it's address offset.

For fixing that problem, we have to use the linker. It will take all the object files and resolve all these symbols (
void
func();
 in our example). If the linker somehow is unable to do that it throws a error like 
unresolved
external symbol
void
func()
. This may happen if you don't give the 
func.o
 object
file to the linker. So, let's give all the object files we have to the linker:
ld main.o func.o -o test


The linker will go through 
main.o
,
then through 
func.o
,
try to resolve symbols and if it goes okay - put it's output to the 
test
 file.
If we look the produced output we will see all symbols are resolved:
$ nm test
0000000000601000 R __bss_start
0000000000601000 R _edata
0000000000601000 R _end
00000000004000b0 T func
00000000004000b7 T main


Here our job is done. Let's look the situation with dynamic(shared) libraries. Let's make a shared library from our 
func.c
 source
file:
gcc -c func.c -o func.o
gcc -shared -fPIC -Wl,-soname,libfunc.so.1 -o libfunc.so.1.5.0 func.o


Voila, we have it. Now, let's put it into known dynamic linker library path, 
/usr/lib/
:
sudo mv libfunc.so.1.5.0 /usr/lib/ # to make program be able to run
sudo ln -s libfunc.so.1.5.0 /usr/lib/libfunc.so.1  #creating symlink for the program to run
sudo ln -s libfunc.so.1 /usr/lib/libfunc.so # to make compilation possible


And let's make our project depend on that shared library by leaving 
func()
 symbol
unresolved after compilation and static linkage process, creating an executable and linking it (dynamically) to our shared library (
libfunc
):
cc main.c -lfunc


Now if we look for the symbol in it's symbols table we still have our symbol unresolved:
$ nm a.out | grep fun
U func


But this is not a problem anymore because 
func
 symbol
will be resolved by dynamic loader before each program start. Okay, now let's back to the theory.

Libraries, in fact, are just an object files which are placed into a single archive by using 
ar
 tool
with a single symbols table which is created by 
ranlib
 tool.

Compiler, when compiling object files, does not resolve 
symbols
.
These symbols will be replaced to addresses by linker. So resolving symbols can be done by two things: 
the
linker
 and 
dynamic
loader
:

The linker: 
ld
,
does 2 jobs: 

a) For static libs or simple object files, this linker changes external symbols in the object files to the addresses of the real entities. For example, if we use C++ name mangling linker will change 
_ZNK3MapI10StringName3RefI8GDScriptE10ComparatorIS0_E16DefaultAllocatorE3hasERKS0_
 to 
0x07f4123f0
.

b) For dynamic libs it only checks if the symbols can
be resolved (you try to link with correct library) at all but does not replace the symbols by address. If symbols can't be resolved (for example they are not implemented in the shared library you are linking to) - it throws 
undefined
reference to
 error and breaks up the building process because you try to use these symbols but linker can't find such symbol in it's object files which it is processing at this time. Otherwise, this linker adds some information to the 
ELF
 executable
which is:

i. 
.interp
 section
- request for an 
interpreter
 -
dynamic loader to be called before executing, so this section just contains a path to the dynamic loader. If you look at your executable which depends on shared library (
libfunc
)
for example you will see the interp section 
$
readelf -l a.out
:
INTERP         0x0000000000000238 0x0000000000400238 0x0000000000400238
0x000000000000001c 0x000000000000001c  R      1
[Requesting program interpreter: /lib64/ld-linux-x86-64.so.2]


ii. 
.dynamic
 section
- a list of shared libraries which 
interpreter
 will
be looking for before executing. You may see them by 
ldd
 or 
readelf
:
$ ldd a.out
linux-vdso.so.1 =>  (0x00007ffd577dc000)
libfunc.so.1 => /usr/lib/libfunc.so.1 (0x00007fc629eca000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007fefe148a000)
/lib64/ld-linux-x86-64.so.2 (0x000055747925e000)

$ readelf -d a.out

Dynamic section at offset 0xe18 contains 25 entries:
Tag        Type                         Name/Value
0x0000000000000001 (NEEDED)             Shared library: [libfunc.so.1]
0x0000000000000001 (NEEDED)             Shared library: [libc.so.6]


Note that 
ldd
 also
finds all the libraries in your filesystem while readelf only shows what libraries does your program need. So, all of these libraries will be searched by dynamic loader (next paragraph). The linker works at build
time.

Dynamic loader: 
ld.so
 or 
ld-linux
.
It finds and loads all the shared libraries needed by a program (if they were not loaded before), resolves the symbols by replacing them to real addresses right before start of the program, prepares the program to run, and then runs it. It works after
build and before running the program. Less speaking, dynamic linking means resolving symbols in your executable before each program start.

Actually, when you run an 
ELF
 executable
with 
.interp
 section
(it needs to load some shared libraries) the OS (Linux) runs an interpreter at first but not your program. Otherwise you have an undefined behavior - you have symbols in your program but they are not defined by addresses which usually means that the program
will be unable to work properly.

You may also run dynamic loader by yourself but it is unnecessary (binary is 
/lib/ld-linux.so.2
for
32-bit architecture elf and 
/lib64/ld-linux-x86-64.so.2
 for
64-bit architecture elf).

Why does the linker claim that 
/usr/bin/ld:
cannot find -lblpapi3_64
 in your case? Because it tries to find all the libraries in it's known paths. Why does it search the library if it will be loaded during runtime? Because it needs to check if all the needed symbols can be resolved by this library
and to put it's name into the 
.dynamic
 section
for dynamic loader. Actually, the 
.interp
 section
exists in almost every c/c++ elf because the 
libc
 and 
libstdc++
 libraries
are both shared, and compiler by default links any project dynamically to them. You may link them statically as well but this will enlarge the total executable size. So, if the shared library can't be found your symbols will remain unresolved and you will
be UNABLE to run your application, thus it can't produce an executable. You may get the list
of directories where libraries are usually searched by:

Passing a command to the linker in compiler arguments.

By parsing 
ld
--verbose
's output.

By parsing 
ldconfig
's
output.

Some of these methods are explained here.

Dynamic loader tries to find all the libraries by using:

DT_RPATH
 dynamic
section of ELF file.

DT_RUNPATH
 section
of the executable.

LD_LIBRARY_PATH
 environment
variable.

/etc/ld.so.cache
 -
own cache file which contains a compiled list of candidate libraries previously found in the augmented library path.

Default paths: In the default path /lib, and then /usr/lib. If the binary was linked with 
-z
nodeflib
 linker option, this step is skipped.

ld-linux
search algorithm

Also, note please, that if we are talking about shared libraries, they are not named 
.so
 but
in 
.so.version
 format
instead. When you build your application the linker will look for 
.so
 file
(which is usually a symlink to 
.so.version
)
but when you run your application the dynamic loader looks for 
.so.version
 file
instead. For example, let's say we have a library 
test
 which
version is 
1.1.1
 according
to semver.
In the filesystem it will look like:
/usr/lib/libtest.so -> /usr/lib/libtest.so.1.1.1
/usr/lib/libtest.so.1 -> /usr/lib/libtest.so.1.1.1
/usr/lib/libtest.so.1.1 -> /usr/lib/libtest.so.1.1.1
/usr/lib/libtest.so.1.1.1


So, to be able to compile you must have all of versioned files (
libtest.so.1
libtest.so.1.1
and 
libtest.so.1.1.1
)
and a 
libtest.so
 file
but for running your app you must have only 3 versioned library files listed first. This also explains why do debian or rpm packages have 
devel
-packages
separately: normal one (which consists only of the files needed by already compiled applications for running them) which has 3 versioned library files and a devel package which has only symlink file for making it possible to compile the project.

Resume

After all of that:

You, your colleague and EACH user of your application code must have all the libraries in their
system linker paths to be able to compile (build your application). Otherwise, they have to change Makefile (or compile command) to add the shared library location directory by adding 
-L<somePathToTheSharedLibrary>
 as
argument.

After successful build you also need your library again to be able to run the program. Your library will be searched by dynamic loader (
ld-linux
)
so it needs to be in it's paths (see above) or in system linker paths. In most of linux program
distributions, for example, games from steam, there is a shell-script which sets the 
LD_LIBRARY_PATH
 variable
which points to all shared libraries needed by the game.
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: