LeetCode | 455. Assign Cookies 贪心算法水题
2018-01-02 13:33
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Assumeyou are an awesome parent and want to give your children some cookies. But, youshould give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child willbe content with; and each cookie j has a size sj.If sj >= gi, we can assign the cookie j to thechild i, and the child i will be content. Your goal is to maximize the numberof your content children and output the maximum number.
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.
Example1:
Input: [1,2,3], [1,1]
Output: 1
Explanation: You have 3 children and 2 cookies. Thegreed factors of 3 children are 1, 2, 3.
And even though you have 2 cookies, since their size is both1, you could only make the child whose greed factor is 1 content.
You need to output 1.
Example2:
Input: [1,2], [1,2,3]
Output: 2
Explanation: You have 2 children and 3 cookies. Thegreed factors of 2 children are 1, 2.
You have 3 cookies and their sizes are big enough to gratifyall of the children,
You need to output 2.
水题,使用贪心算法解决
class Solution {
public:
intfindContentChildren(vector<int>& g, vector<int>& s) {
sort(g.begin(),g.end());
sort(s.begin(),s.end());
int t=0; int count=0;
for(int i=0;i<g.size();i++)
{
while(t<s.size()&&s[t]<g[i]) t++;
if(t==s.size()) break;
count++;
t++;
}
return count;
}
};
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.
Example1:
Input: [1,2,3], [1,1]
Output: 1
Explanation: You have 3 children and 2 cookies. Thegreed factors of 3 children are 1, 2, 3.
And even though you have 2 cookies, since their size is both1, you could only make the child whose greed factor is 1 content.
You need to output 1.
Example2:
Input: [1,2], [1,2,3]
Output: 2
Explanation: You have 2 children and 3 cookies. Thegreed factors of 2 children are 1, 2.
You have 3 cookies and their sizes are big enough to gratifyall of the children,
You need to output 2.
水题,使用贪心算法解决
class Solution {
public:
intfindContentChildren(vector<int>& g, vector<int>& s) {
sort(g.begin(),g.end());
sort(s.begin(),s.end());
int t=0; int count=0;
for(int i=0;i<g.size();i++)
{
while(t<s.size()&&s[t]<g[i]) t++;
if(t==s.size()) break;
count++;
t++;
}
return count;
}
};
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