C++ STL算法之accumulate函数

#include <bits/stdc++.h>
using namespace std;

int main()
{
vector<int> q;
for(int i=0;i<21;i++)
{
q.push_back(i);
}
int a=accumulate ( q.begin ( ) , q.end ( ) , 0 );
printf("%d",a);
return 0;
}

vector <int> v3, v4( 10 );
vector <int>::iterator Iter3, Iter4;

int s;
for ( s = 1 ; s < 11 ; s++ )
{
v3.push_back( s );
}

cout << "向量v3的初始值分别为:\n ( " ;
for ( Iter3 = v3.begin( ) ; Iter3 != v3.end( ) ; Iter3++ )
cout << *Iter3 << " ";
cout << ")." << endl;

int ptotal;
ptotal = accumulate ( v3.begin ( ) , v3.end ( ) , 1 , multiplies<int>( ) );

cout << "整数1到10的连乘积为: "
<< ptotal << "." << endl;

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