pandas层次化索引
2017-12-29 18:03
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import pandas as pd import numpy as np from numpy import nan as NA df=pd.DataFrame(np.random.randn(7,3),index=['a','b','c','d','e','f','g'],columns=['q','w','t']) In [106]:df Out[120]: q w t a 0.351629 -1.586787 0.557937 b -0.579714 0.497142 -1.949643 c 0.444369 -0.924846 1.210504 d -0.695731 0.399221 -1.152604 e -0.723842 0.523469 -0.443298 f 0.689071 0.388882 -0.268371 g 0.311272 0.637418 -0.935549 df.loc['a':'e','w']=NA df.loc['a':'c','t']=NA In [106]: df Out[123]: q w t a 0.351629 NaN NaN b -0.579714 NaN NaN c 0.444369 NaN NaN d -0.695731 NaN -1.152604 e -0.723842 NaN -0.443298 f 0.689071 0.388882 -0.268371 g 0.311272 0.637418 -0.935549 In [106]: df.fillna(method='bfill',limit=3) Out[124]: q w t a 0.351629 NaN -1.152604 b -0.579714 NaN -1.152604 c 0.444369 0.388882 -1.152604 d -0.695731 0.388882 -1.152604 e -0.723842 0.388882 -0.443298 f 0.689071 0.388882 -0.268371 g 0.311272 0.637418 -0.935549 frame=pd.DataFrame(np.arange(12).reshape((4,3)),index=[['a','a','b','b'],[1,2,1,2]],columns=[['oo','oo','cc'],['gg','rr','gg']]) In [106]: frame#分层索引 Out[106]: oo cc gg rr gg a 1 0 1 2 2 3 4 5 b 1 6 7 8 2 9 10 11 frame.index.names=['key1','key2'] frame.columns.names=['state','color'] In [108]: frame#名字 Out[108]: state oo cc color gg rr gg key1 key2 a 1 0 1 2 2 3 4 5 b 1 6 7 8 2 9 10 11 In [108]: frame['oo']#列索引 Out[109]: color gg rr key1 key2 a 1 0 1 2 3 4 b 1 6 7 2 9 10 In [108]: frame.swaplevel('key1','key2')#接受两个级别编号或名称,返回一个互换级别的新对象 Out[110]: state oo cc color gg rr gg key2 key1 1 a 0 1 2 2 a 3 4 5 1 b 6 7 8 2 b 9 10 11 In [108]: frame.sort_index(1)#根据单个级别中的值对数据进行排序 Out[111]: state cc oo color gg gg rr key1 key2 a 1 2 4000 0 1 2 5 3 4 b 1 8 6 7 2 11 9 10 In [108]: frame.swaplevel(0,1).sort_index(0) Out[112]: state oo cc color gg rr gg key2 key1 1 a 0 1 2 b 6 7 8 2 a 3 4 5 b 9 10 11 In [108]: frame.sum(level='key2')#指定在某条轴上求和的级别 Out[114]: state oo cc color gg rr gg key2 1 6 8 10 2 12 14 16 In [108]: frame.sum(level='color',axis=1) Out[117]: color gg rr key1 key2 a 1 2 1 2 8 4 b 1 14 7 2 20 10
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