Leetcode#717. 1-bit and 2-bit Characters
2017-12-24 22:31
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题目链接
We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.
Example 1:
Input:
bits = [1, 0, 0]
Output: True
Explanation:
The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.
Example 2:
Input:
bits = [1, 1, 1, 0]
Output: False
Explanation:
The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.
Note:
1 <= len(bits) <= 1000.
bits[i] is always 0 or 1.
题意
我们现在有以下两种字符串1. “10”和”11”为two-bit
2. “0”为one-bit
现在由以上两种组成的一个数组,判断组成数组的最后一个是不是one-bit,如果是输出“true”,否则输出”false”.
Python语言
class Solution(object): def isOneBitCharacter(self, bits): """ :type bits: List[int] :rtype: bool """ i = 0 while i<len(bits): if bits[i] == 0: step = 1 i = i + 1 else: step = 2 i = i + 2 print step if step == 1: return True else: return False
C++语言
class Solution { public: bool isOneBitCharacter(vector<int>& bits) { int len = bits.size(),step=0; for(int i=0; i<len; i+=step) { if(bits[i]==0) step = 1; else step = 2; } if(step==1) return true; else return false; } };
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