LeetCode-026 Remove Duplicates from Sorted Array
2017-12-10 18:36
531 查看
Description
Given a sorted array, remove the duplicates in-place such that each element appear only once and return the new length.Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
Example
Given nums = [1,1,2],Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively.
It doesn’t matter what you leave beyond the new length.
Analyse
题意为去除一个有序数组中的重复的值,要求空间复杂度为常数级。既然要求复杂度为常数级,那么就是说,整个操作都是在原数组内完成的,所以我们只需要将不重复的元素提前到前面来就行,也是一道基础的题。Code
class Solution { public: int removeDuplicates(vector<int>& nums) { int count=0; for (int i=1;i<nums.size();i++) { if (nums[i]==nums[i-1]) count++; else nums[i-count] = nums[i]; } return nums.size()-count; } };
相关文章推荐
- Java for LeetCode 026 Remove Duplicates from Sorted Array
- LeetCode 026 Remove Duplicates from Sorted Array
- 2017-09-12 LeetCode_026 Remove Duplicates from Sorted Array
- leetcode 026 —— Remove Duplicates from Sorted Array
- leetcode_026 Remove Duplicates from Sorted Array
- leetcode_c++:Remove Duplicates from Sorted Array(026)
- leetcode 026 Remove Duplicates from Sorted Array(难易度:Easy)
- [LeetCode]026-Remove Duplicates from Sorted Array
- leetcode-026 Remove Duplicates from Sorted Array
- LeetCode 026 Remove Duplicates from Sorted Array
- [LeetCode]题解(python):026-Remove Duplicates from Sorted Array
- LeetCode(026) Remove Duplicates from Sorted Array (Java)
- 【LeetCode-面试算法经典-Java实现】【026-Remove Duplicates from Sorted Array(删除排序数组中的重复元素)】
- LeetCode 026 Remove Duplicates from Sorted Array
- leetcode解题方案--026--Remove Duplicates from Sorted Array
- LeetCode 80:Remove Duplicates from Sorted Array II
- LeetCode-26-Remove Duplicates from Sorted Array(消除已排序数组中的重复元素)
- LeetCode 80 Remove Duplicates from Sorted Array II
- LeetCode Remove Duplicates from Sorted Array
- leetcode--Remove Duplicates from Sorted Array