Leetcode:728. Self Dividing Numbers
2017-12-06 15:16
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问题重述:
考虑到时间复杂度的优化应该少用for循环,利用python中参数类型强制转换,且str类型是可迭代类型:
遍历digit寻找全部符合要求的非零数字,采用filter()函数来代替fo,filter的用法见:http://blog.csdn.net/SeeTheWorld518/article/details/46975897,简化代码:
A self-dividing number is a number that is divisible by every digit it contains. For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0. Also, a self-dividing number is not allowed to contain the digit zero. Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible. Example 1: Input: left = 1, right = 22 Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22] Note: The boundaries of each input argument are 1 <= left <= right <= 10000.
考虑到时间复杂度的优化应该少用for循环,利用python中参数类型强制转换,且str类型是可迭代类型:
for digit in str(num))
遍历digit寻找全部符合要求的非零数字,采用filter()函数来代替fo,filter的用法见:http://blog.csdn.net/SeeTheWorld518/article/details/46975897,简化代码:
def selfDividingNumbers(left, right): dividing = lambda num: '0' not in str(num) and all(num % int(digit) == 0 for digit in str(num)) return filter(dividing, range(left, right + 1))
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