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SJTU OJ 1056 二哥吃糖

2017-12-02 00:20 302 查看

SJTU OJ 1056 二哥吃糖

原题链接

这道题查找第q大的糖果数用平衡树就可以(平衡度用结点个数而不是高度,返回第q大更快)。其他要注意的就是标记好几号盒子并到了几号盒子里。初始化第i个糖果在第i个盒子里。

下面是代码:

#include <iostream>
#include <cstdio>
using namespace std;
int m, n;
int box[500005];//每个盒子多少个糖;
int sugar[500005];//每个糖属于几号盒子;
int movebox[500005] = {0};//每个盒子合并到哪个盒子;
int boxnum;
template<class T>
class BinarySearchTree{
private:
struct BinaryNode{
T data;
BinaryNode * left;
BinaryNode * right;
int height;
BinaryNode(const T& otherdata, BinaryNode * otherl, BinaryNode * otherr):data(otherdata), left(otherl), right(otherr), height(1){}
};
public:
BinarySearchTree(BinaryNode * t = NULL){root = t;}
~BinarySearchTree() {makeEmpty(root);}
bool find(const T& x)const{
return find(x, root);
}
void insert(const T& x){
insert(x, root);
}
void remove(const T& x){
remove(x, root);
}
T& findkth(int i){
return findkth(i, root);
}
private:
BinaryNode * root;
void insert(const T& x, BinaryNode * &t){
if (t==NULL) t = new BinaryNode(x, NULL, NULL);
else if (x>t->data) {
insert(x, t->left);
if (h(t->left)-h(t->right) == 2){
if (x > t->left->data){
LL(t);
}
else LR(t);
}
t->height = h(t->left) + h(t->right) + 1;
}
else {
insert(x, t->right);
if (h(t->right)-h(t->left) == 2){
if (x <= t->right->data){
RR(t);
}
else RL(t);
}
t->height = h(t->left) + h(t->right) + 1;
}
}
void remove(const T& x, BinaryNode * &t){
if (t == NULL) return;
if (x>t->data) {
remove(x, t->left);
if (h(t->right) - h(t->left) == 2){
BinaryNode *r =  t->right;
if (h(r->left) > h(r->right))
RL(t);
else
RR(t);
}
t->height = h(t->left) + h(t->right) + 1;
}
else if (x<t->data) {
remove(x, t->right);
if (h(t->left) - h(t->right) == 2){
BinaryNode *r =  t->left;
if (h(r->right) > h(r->left))
LR(t);
else
LL(t);
}
t->height = h(t->left) + h(t->right) + 1;
}
else if (t->left != NULL && t->right != NULL){
if (h(t->left) <= h(t->right)){
BinaryNode * tmp = t->right;
while(tmp->left != NULL) tmp = tmp->left;
t->data = tmp->data;
remove(t->data, t->right);
t->height = h(t->left) + h(t->right) + 1;
}
else{
BinaryNode * tmp = t->left;
while (tmp->right != NULL) tmp = tmp->right;
t->data = tmp->data;
remove(t->data, t->left);
t->height = h(t->left) + h(t->right) + 1;
}
}
else{
BinaryNode * old = t;
t = (t->left != NULL) ? t->left : t->right;
delete old;
}
}
bool find(const T& x, BinaryNode * t)const{
if (t == NULL) return false;

if (x>t->data) return find(x, t->left);
if (x<t->data) return find(x, t->right);

return true;
}
void makeEmpty(BinaryNode * &t){
if (t == NULL) return;
BinaryNode * tmp = t;
makeEmpty(t->left);
makeEmpty(t->right);
delete tmp;
t = NULL;
}
T& findkth(int i, BinaryNode *&t){
int rs = h(t->left);
if (rs == i-1){
return t->data;
}

if (rs >= i) return findkth(i, t->left);
else return findkth(i-rs-1, t->right);
}
int h(BinaryNode * t){
return t==NULL ? 0 : t->height;
}
void LL(BinaryNode *&t){
BinaryNode * t1 = t->left;
t->left = t1->right;
t1->right = t;
t->height = h(t->left) + h(t->right) + 1;
t1->height = h(t1->left) + h(t)+1;
t = t1;
}
void RR(BinaryNode *&t){
BinaryNode * t1 = t->right;
t->right = t1->left;
t1->left = t;
t->height = h(t->left) + h(t->right) + 1;
t1->height = h(t1->right) + h(t)+1;
t = t1;
}
void LR(BinaryNode *&t){
RR(t->left);
LL(t);
}
void RL(BinaryNode *&t){
LL(t->right);
RR(t);
}
};
int main()
{
scanf("%d%d", &n, &m);
BinarySearchTree<int> t;
for (int i=1; i<=n; i++){
box[i] = 1;
t.insert(1);
sugar[i] = i;
}
boxnum = n;
char query;
int x, y;
while (m--){
query = getchar();
query = getchar();
switch(query){
case 'C':
scanf("%d%d", &x, &y);
while (movebox[sugar[x]] != 0){//找到x糖果现在在几号盒子;
sugar[x] = movebox[sugar[x]];
}
while (movebox[sugar[y]] != 0){//找到y糖果现在在几号盒子;
sugar[y] = movebox[sugar[y]];
}
if (sugar[y] != sugar[x] && box[sugar[x]] != 0 && box[sugar[y]] != 0){
t.remove(box[sugar[x]]);
t.remove(box[sugar[y]]);
box[sugar[x]] += box[sugar[y]];
t.insert(box[sugar[x]]);
box[sugar[y]] = 0;
movebox[sugar[y]] = sugar[x];//y的盒子移动到x的盒子;
boxnum--;
}
break;
case 'D':
scanf("%d", &x);
while (movebox[sugar[x]] != 0){//同上;
sugar[x] = movebox[sugar[x]];
}
if (box[sugar[x]] != 0){
t.remove(box[sugar[x]]);
box[sugar[x]] = 0;
boxnum--;
}
break;
case 'Q':
scanf("%d", &x);
if (boxnum < x) printf("%d\n", 0);
else{
printf("%d\n", t.findkth(x));
}
break;
default:
cout << "Wrong!\n";
break;
}
}
return 0;
}


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标签:  SJTUOJ C++ 算法题