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Codeforces 892 A.Greed

2017-11-18 22:51 281 查看
A. Greed

time limit per test
2 seconds

memory limit per test
256 megabytes

input
standard input

output
standard output

Jafar has n cans of cola. Each can is described by two integers: remaining volume of cola ai and can's capacity bi (ai  ≤  bi).

Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not!

Input
The first line of the input contains one integer n (2 ≤ n ≤ 100 000) — number of cola cans.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 109) — volume of remaining cola in cans.

The third line contains n space-separated integers that b1, b2, ..., bn (ai ≤ bi ≤ 109) — capacities of the cans.

Output
Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Examples

input
2
3 5
3 6


output
YES


input
3
6 8 9
6 10 12


output
NO


input
5
0 0 5 0 0
1 1 8 10 5


output
YES


input
4
4 1 0 3
5 2 2 3


output
YES


Note
In the first sample, there are already 2 cans, so the answer is "YES".

分析:签到题,排个序看容量最大的杯子能否装下.

#include <cstdio>
#include <cmath>
#include <queue>
#include <cstring>
#include <iostream>
#include <algorithm>

using namespace std;

long long n, a[100010], b[100010], sum;

int main()
{
cin >> n;
for (int i = 1; i <= n; i++)
{
long long t;
cin >> t;
sum += t;
}
for (int i = 1; i <= n; i++)
cin >> b[i];
sort(b + 1, b + 1 + n);
if (sum <= b
+ b[n - 1])
puts("YES");
else
puts("NO");

return 0;
}
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