007_LeetCode_7 Reverse Integer 题解
2017-11-18 19:38
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Description:
Given a 32-bit signed integer, reverse digits of an integer.翻转一个整数但是要考虑溢出。
java代码:
class Solution { public int reverse(int x) { int res = 0; while (x != 0){ int tail = x % 10; int result = res * 10 + tail; if (result - tail) / 10 != res){ return 0; } res = result; x = x / 10; } return res; } }
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