leetcode 58. Length of Last Word
2017-11-16 10:16
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58. Length of Last Word
Given a string s consists of upper/lower-case alphabets and empty space characters
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example:
Given a string s consists of upper/lower-case alphabets and empty space characters
' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example:
Input: "Hello World" Output: 5
class Solution { public: int lengthOfLastWord(string s) { for (int i = s.size() - 1; i >= 0; i--) { if (s[i] != ' ') //i确定最后一个单词的最后一个字母 { for(int j = i; j >= 0; j--) //确定最后一个单词的第一个字母 { if (s[j] == ' ') { return i - j; } } return i + 1; } } return 0; } };
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