python 练习-登录接口

# python 3.6 登录接口练习
# _*_ coding:utf-8 _*_
import sys
import os
import getpass

i=0
while i < 3  :
username = input("请输入用户名：")
with open("account_lock.txt","r") as account_lock_file :   #打开锁定用户文件，r为只读
account_lock_list = account_lock_file.readlines()  #转换成列表

for lock_name in account_lock_list :   #循环遍历文件
lock_name = lock_name.strip('\n')  #去掉换行符
if username == lock_name :
sys.exit("用户{_username}已被锁定，请联系管理员解锁！！".format(_username=username))

#password =input("请输入密码：")
with open("accounts.txt",'r') as account_file :
account_list = account_file.readlines()
for account_line in account_list :
(name,pas) = account_line.strip('\n').split()  #去掉换行符，并以，为切片

if username == name :
j = 0
while j < 3 :
password = getpass.getpass("请输入用户密码：")
if password == pas :
print("用户{_name}登录成功".format(_name = username))
sys.exit()
else:
if j != 2 :
print("用户{_name}密码输入错误，请重新输入，还有{d}次机会".format(_name = username,d=2-j))
j = j + 1
else:
with open("account_lock.txt",'a+') as account_lock_file :
account_lock_file.write(username +'\n')
sys.exit("超过最大错误次数，用户{_name}已被锁定，并退出".format(_name=username))
else:
pass
else:
if i != 2 :
print("用户{_name}不存在，请重新输入，还有{d}次机会！".format(_name = username,d=2-i))
i = i + 1  #当用户输入用户名错误时增加错误次数
else:
sys.exit("用户{_username}不存在，系统即将退出".format(_username=username))