83. Remove Duplicates from Sorted List
2017-11-09 23:02
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Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given
Given
链表去掉重复的元素。程序如下:
这个解法还是不够严谨,因为链表中第一个元素可能为Integer.MAX_VALUE,会导致判断出错,为了严谨,可以先判断第一个元素值是否满足条件,从第二个元素开始做比较即可。
For example,
Given
1->1->2, return
1->2.
Given
1->1->2->3->3, return
1->2->3.
链表去掉重复的元素。程序如下:
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution { public ListNode deleteDuplicates(ListNode head) { ListNode pre = new ListNode(Integer.MAX_VALUE); ListNode tmp = pre; while (head != null){ if (head.val == pre.val){ head = head.next; continue; } pre.next = head; pre = head; head = head.next; } pre.next = head; return tmp.next; } }
这个解法还是不够严谨,因为链表中第一个元素可能为Integer.MAX_VALUE,会导致判断出错,为了严谨,可以先判断第一个元素值是否满足条件,从第二个元素开始做比较即可。
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