HDU 5929 Basic Data Structure
2017-11-08 15:42
393 查看
Mr. Frog learned a basic data structure recently, which is called stack.There are some basic operations of stack:
∙∙ PUSH
x: put x on the top of the stack, x must be 0 or 1.
∙∙ POP:
throw the element which is on the top of the stack.
Since it is too simple for Mr. Frog, a famous mathematician who can prove "Five points coexist with a circle" easily, he comes up with some exciting operations:
∙∙REVERSE:
Just reverse the stack, the bottom element becomes the top element of the stack, and the element just above the bottom element becomes the element just below the top elements... and so on.
∙∙QUERY:
Print the value which is obtained with such way: Take the element from top to bottom, then do NAND operation one by one from left to right, i.e. If atop,atop−1,⋯,a1atop,atop−1,⋯,a1 is
corresponding to the element of the Stack from top to the bottom, value=atopvalue=atop nand atop−1atop−1 nand
... nand a1a1.
Note that the Stack will not change after QUERY operation. Specially, if the Stack is empty now,you need to print ” Invalid.”(without quotes).
By the way, NAND is a basic binary operation:
∙∙ 0
nand 0 = 1
∙∙ 0
nand 1 = 1
∙∙ 1
nand 0 = 1
∙∙ 1
nand 1 = 0
Because Mr. Frog needs to do some tiny contributions now, you should help him finish this data structure: print the answer to each QUERY, or tell him that is invalid.
InputThe first line contains only one integer T (T≤20T≤20),
which indicates the number of test cases.
For each test case, the first line contains only one integers N (2≤N≤2000002≤N≤200000),
indicating the number of operations.
In the following N lines, the i-th line contains one of these operations below:
∙∙ PUSH
x (x must be 0 or 1)
∙∙ POP
∙∙ REVERSE
∙∙ QUERY
It is guaranteed that the current stack will not be empty while doing POP operation.
OutputFor each test case, first output one line "Case #x:w, where x is the case number (starting from 1). Then several lines follow, i-th line contains an integer indicating the answer to the i-th QUERY operation. Specially, if the i-th QUERY is invalid,
just print " Invalid."(without quotes). (Please see the sample for more details.)
Sample Input
Sample Output
Hint
∙∙ PUSH
x: put x on the top of the stack, x must be 0 or 1.
∙∙ POP:
throw the element which is on the top of the stack.
Since it is too simple for Mr. Frog, a famous mathematician who can prove "Five points coexist with a circle" easily, he comes up with some exciting operations:
∙∙REVERSE:
Just reverse the stack, the bottom element becomes the top element of the stack, and the element just above the bottom element becomes the element just below the top elements... and so on.
∙∙QUERY:
Print the value which is obtained with such way: Take the element from top to bottom, then do NAND operation one by one from left to right, i.e. If atop,atop−1,⋯,a1atop,atop−1,⋯,a1 is
corresponding to the element of the Stack from top to the bottom, value=atopvalue=atop nand atop−1atop−1 nand
... nand a1a1.
Note that the Stack will not change after QUERY operation. Specially, if the Stack is empty now,you need to print ” Invalid.”(without quotes).
By the way, NAND is a basic binary operation:
∙∙ 0
nand 0 = 1
∙∙ 0
nand 1 = 1
∙∙ 1
nand 0 = 1
∙∙ 1
nand 1 = 0
Because Mr. Frog needs to do some tiny contributions now, you should help him finish this data structure: print the answer to each QUERY, or tell him that is invalid.
InputThe first line contains only one integer T (T≤20T≤20),
which indicates the number of test cases.
For each test case, the first line contains only one integers N (2≤N≤2000002≤N≤200000),
indicating the number of operations.
In the following N lines, the i-th line contains one of these operations below:
∙∙ PUSH
x (x must be 0 or 1)
∙∙ POP
∙∙ REVERSE
∙∙ QUERY
It is guaranteed that the current stack will not be empty while doing POP operation.
OutputFor each test case, first output one line "Case #x:w, where x is the case number (starting from 1). Then several lines follow, i-th line contains an integer indicating the answer to the i-th QUERY operation. Specially, if the i-th QUERY is invalid,
just print " Invalid."(without quotes). (Please see the sample for more details.)
Sample Input
2 8 PUSH 1 QUERY PUSH 0 REVERSE QUERY POP POP QUERY 3 PUSH 0 REVERSE QUERY
Sample Output
Case #1: 1 1 Invalid. Case #2: 0
Hint
In the first sample: during the first query, the stack contains only one element 1, so the answer is 1. then in the second query, the stack contains 0, l (from bottom to top), so the answer to the second is also 1. In the third query, there is no element in the stack, so you should output Invalid. 双端队列+模拟
#include<cstdio> #include<queue> #include<cstring> #include<algorithm> using namespace std; const int N = 1e5 + 10; const int INF = 0x7FFFFFFF; const int mod = 1e9 + 7; const int M = 3e5; const int low(int x) { return x&-x; } int T, n, x; char s ; int a[N<<3]; int main(){ int cas = 1; for (scanf("%d",&T);T--;cas++) { scanf("%d",&n); int l = M, r= M - 1,now = 1; printf("Case #%d:\n",cas); deque<int> b; while (n--) { scanf("%s",s); if (!strcmp(s,"PUSH")) { scanf("%d",&x); if (now) { a[++r] = x; if (!x) b.push_back(r); } else { a[--l] = x; if (!x) b.push_front(l); } } else if (!strcmp(s,"REVERSE")) { now^=1; } else if (!strcmp(s,"POP")) { if (now) { if (!a[r]) { b.pop_back(); } --r; } else { if (!a[l]) { b.pop_front(); } ++l; } } else { if (l>r) { printf("Invalid.\n"); } else if (b.empty()) { printf("%d\n",(r-l+1)%2); } else if (now == 0) { if (b.back() == l) printf("%d\n",(r-l)%2); else printf("%d\n",(r-b.back()+1)%2); } else { if (b.front() == r) printf("%d\n",(r-l)%2); else printf("%d\n",(b.front()-l+1)%2); } } } } return 0; }
相关文章推荐
- Basic Data Structure(HDU 5929 2016东北地区CCPC)
- Basic Data Structure HDU 5929(模拟)
- HDU 5929 Basic Data Structure(双端队列)
- HDU-5929 Basic Data Structure
- 双端队列+与非运算——Basic Data Structure ( HDU 5929 )
- HDU 5929 Basic Data Structure(deque双向队列+找规律)
- hdu 5929 Basic Data Structure(山东CCPC)
- hdu 5929 Basic Data Structure(双端队列+模拟)
- HDU - 5929 Basic Data Structure(模拟+规律)
- hdu 5929 Basic Data Structure(找规律+deque模拟)
- hdu 5929 Basic Data Structure
- H - Basic Data Structure HDU - 5929
- hdu-5929 Basic Data Structure(双端队列+模拟)
- HDU 5929 Basic Data Structure
- hdu 5929 CCPC东北四省赛H - Basic Data Structure
- Basic Data Structure hdu 5929
- hdu 5929 Basic Data Structure(找规律,模拟)
- HDU 5929 Basic Data Structure(模拟,deque)——2016CCPC东北地区大学生程序设计竞赛 - 重现赛
- HDU 5292 Basic Data Structure
- HDU Basic Data Structure 2016CCPC东北地区大学生程序设计竞赛 - 重现赛