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iOS-打开外部应用、Safari、邮箱等

2017-11-08 11:44 537 查看
1:打开Safari

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.baidu.com"]];


2:打电话

NSString *num = @"110"; //number为号码字符串
NSString *mobileNumber = [NSString stringWithFormat:@"telprompt://%@", num];
NSLog(@"call phone %@;", mobileNumber);
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:mobileNumber]];


提示:上面代码触发后,系统会提示用户是否真的要打电话, 电话结束后,会返回至应用程序,

如果将telprompt修改为:tel 后,点击可直接拨打电话, 但电话结束后,不会返回至应用程序

3:打开Mail

NSString *recipients = @"mailto:ysy@flyrise.cn?subject=Hello from California!";
NSString *body = @"&body=It is raining in sunny California!";
NSString *email = [NSString stringWithFormat:@"%@%@", recipients, body];
email = [email stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:email]];


4:打开Messages

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"sms://800888"]];


5:打开App Store 某个应用的评价系统

NSLog(@"%@",[[[SystemGlobalInfo defaultInstance] deviceInfo] applicationId]);
NSString *str = [NSString stringWithFormat: @"itms-apps://ax.itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id=%@",[[[SystemGlobalInfo defaultInstance] deviceInfo] applicationId]];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:str]];


6:打开App Store 中的某个应用 途中经过Safari

NSString *appID = @"291586600";
NSString *appUrl = [NSString stringWithFormat:@"http://phobos.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=%@&mt=8",appID];
NSURL *appStoreUrl = [NSURL URLWithString:appUrl];
[[UIApplication sharedApplication] openURL:appStoreUrl];


7:打开App Store 中的某个应用 直接跳转

NSString *urlString = @"http://itunes.apple.com/us/app/ye-wu-xie-zuo-ping-tai/id507704613?mt=8&uo=4";
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]] ;


8:打开谷歌Maps进行搜索

NSString* searchQuery = @"珠海";
searchQuery = [searchQuery stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
NSString* urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@", searchQuery];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];


9:利用OpenUrl打开第三方应用程序

本文释权了打开的方式,很详细.. 地址如下:

http://blog.cnrainbird.com/index.php/2012/06/04/tong_guo_openurl_qi_dong_di_san_fang_app_bing_chuan_can_shu/

这里简单描述一下注意点,

1: A工程 需要打开 B 工程 那么B工程需要在plist文件中 进行UrlType的注册

2:在启动其他第三方应用程序之前,可以通过如下代码判断,应用程序是否已经安装在iPhone中.

NSURL *url = [NSURL URLWithString:@"AppMessageDemo:11"];
if ([[UIApplication sharedApplication] canOpenURL:url]) {
[[UIApplication sharedApplication] openURL:url];
}else {
[ShareCode Msg:@"没安装"];
}


3: B工程被打开时,请使用如下委托处理打开的消息

-(BOOL)application:(UIApplication *)application openURL:(NSURL *)url sourceApplication:(NSString *)sourceApplication annotation:(id)annotation
{
NSLog(@"%@",[url path]);
NSLog(@"%@",sourceApplication);
NSLog(@"%@",annotation);
return NO;
}


下面这个委托,也就是微文中提到的委托,已经被苹果弃用

-(BOOL)application:(UIApplication *)application handleOpenURL:(NSURL *)url
{
NSLog(@"123");
return [WXApi handleOpenURL:url delegate:self];
}


注: sourceApplication 表示 App plist文件中标明的 Bundle identifier

至于返回YES,还是返回NO,似乎没有发生任何事情,待继续考证.

10:为应用设置首选项功能

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