codeforces 560A【python】
2017-11-05 18:55
330 查看
只要判断list里面有没有1即可
n = int(raw_input())
line = map(int,raw_input().split())
if 1 in line:
print -1
else:
print 1
n = int(raw_input())
line = map(int,raw_input().split())
if 1 in line:
print -1
else:
print 1
相关文章推荐
- Codeforces 560A
- codeforces 719A 【python】
- codeforces 675 A~E(Round #353 Div. 2) python and C++ 解法
- codeforces 651A python
- python中的eval()+codeforces--116A.Tram
- Python解决codeforces ---- 1
- codeforces 651A python
- Python解决codeforces ---- 5
- Python解决codeforces ---- 2
- 题解-python-CodeForces 227A
- 【63.73%】【codeforces 560A】Currency System in Geraldion
- codeforces_734C python的sort()函数 python的bisect
- 题解-python-CodeForces 227B
- codeforces 731A【python】
- python爬虫抓取codeforces分数
- codeforces 水题练学习下python
- 小比赛(CodeForces 560A,UVA 11040,CodeForces 550B,HDU 1856,UVA 1644,CodeForces 560B,HDU 3405,UVA 10820)
- Python解决codeforces ---- 7
- Python解决codeforces ---- 3
- Review of Codeforces 5A and 5B(Python)