hdu 1517 A Multiplication Game (博弈——找规律)
2017-10-23 14:01
537 查看
A Multiplication Game
Stan and Ollie play the game of multiplication by multiplying an integer p by one of the numbers 2 to 9. Stan always starts with p = 1, does his multiplication, then Ollie multiplies the number, then Stan and so on. Before a game starts, they draw an integer 1 < n < 4294967295 and the winner is who first reaches p >= n.Input
Each line of input contains one integer number n.
Output
For each line of input output one line either
Stan wins.
or
Ollie wins.
assuming that both of them play perfectly.
Sample Input
162
17
34012226
Sample Output
Stan wins.
Ollie wins.
Stan wins.
思路:大数据,所以直接手推小数据找规律
1~9 先手必胜
10~18 后手必胜
19~162 先手必胜
163~324 后手必胜
….
因此,当n>18时,n不断地除以18,最后如果n<=9则先手必胜,否则后手必胜
注意:除要用double
代码:
#include<stdio.h> #include<math.h> #include<string.h> #include<algorithm> using namespace std; int main() { double n; while(~scanf("%lf",&n)) { while(n>18) n/=18; if(n<=9) printf("Stan wins.\n"); else printf("Ollie wins.\n"); } return 0; }
相关文章推荐
- hdu 1517 A Multiplication Game (博弈——找规律)
- HDU_1517_博弈(巧妙规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- HDU 1517 A Multiplication Game(博弈找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1517 A Multiplication Game(博弈找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- HDU 1517 ——A Multiplication Game(博弈)(找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- HDU 1517 A Multiplication Game (博弈、PN态、找规律)*
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1517 A Multiplication Game (博弈——找规律)
- hdu 1564 Play a game(博弈——找规律)