1021. 个位数统计 (15)

原题: https://www.patest.cn/contests/pat-b-practise/1021

完整C语言实现:

#include <stdio.h>

int main () {
char str[1000];
int num[10] = {0};
char *ptr = str;
int cur;
int i;

scanf("%s", str);
while (*ptr != '\0') {
cur = *ptr - '0';
num[cur] += 1;
ptr++;
}

for (i=0; i<10; i++) {
if (num[i] != 0) {
printf("%d:%d\n", i, num[i]);
}
}

return 0;
}