hdu 1228 A+B （字符串处理） 水

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 11543    Accepted Submission(s): 6699

Problem Description

读入两个小于100的正整数A和B,计算A+B.

需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

Sample Output

3
90
96

Source

浙大计算机研究生复试上机考试-2005年

#include <iostream&
4000
gt;
#include <cstring>
#include <stdio.h>
using namespace std;
int value(char c[])
{
int n;
if(!strcmp(c,"zero"))
n=0;
else if(!strcmp(c,"one"))
n=1;
else if(!strcmp(c,"two"))
n=2;
else if(!strcmp(c,"three"))
n=3;
else if(!strcmp(c,"four"))
n=4;
else if(!strcmp(c,"five"))
n=5;
else if(!strcmp(c,"six"))
n=6;
else if(!strcmp(c,"seven"))
n=7;
else if(!strcmp(c,"eight"))
n=8;
else
n=9;
return n;
}
int main()
{
char  a[10],s;
int i=0,sum;
while(cin>>a)
{
sum=value(a);
char b[10],c[10],d[10];
cin>>b;
if(b[0]=='+')
{
cin>>c;
cin>>d;
if(d[0]=='=')
{
sum+=value(c);
cout<<sum<<endl;
}
else
{
cin>>s;
sum+=value(c)*10+value(d);
cout<<sum<<endl;
}
}
else
{
cin>>s>>c;
cin>>d;
if(d[0]=='=')
{
sum=sum*10+value(b)+value(c);
cout<<sum<<endl;
}
else
{
cin>>s;
sum=sum*10+value(b)+value(c)*10+value(d);
cout<<sum<<endl;
}
}
}
return 0;
}