Java中累计时间的计算(以小时为最终结果)

最近在项目中需要用到工作累计时间，所以就就写了一个小方法，作用是可以计算两个时间点之间的累积时间(即累积工作小时)，这里头需要注意的是输入的日期格式为

“yyyy-MM-dd-HH”，目前测试过后，可以计算不同年月日之间的小时差，下面附上主要代码：

public static int workHours(String startTime,String endTime){
String[] startTimes = getStrings(startTime);
for (int i = 0; i < startTimes.length; i++) {
System.out.print(startTimes[i] + " ");
}
System.out.println();
System.out.println("------------------------------");
String[] endTimes = getStrings(endTime);
for (int i = 0; i < endTimes.length; i++) {
System.out.print(endTimes[i] + " ");
}
int workHours = 0;
int workDays = 0;
if (startTimes[0].equals(endTimes[0])) {// 年
if (startTimes[1].equals(endTimes[1])) {// 月
if (startTimes[2].equals(endTimes[2])) {// 同一天的不同小时
workHours = Integer.parseInt(endTimes[3]) - Integer.parseInt(startTimes[3]);
} else {// 同一月不同的一天
workDays = Integer.parseInt(endTimes[2]) - Integer.parseInt(startTimes[2]);
workHours = workDays * 24 + Integer.parseInt(endTimes[3]) - Integer.parseInt(startTimes[3]);
}
} else {// 同一年不同月
String startMs = startTime.substring(0, 10);
String endMs = endTime.substring(0, 10);
Date earlydate = new Date();
Date latedate = new Date();
DateFormat df = DateFormat.getDateInstance();
try {
earlydate = df.parse(startMs);
latedate = df.parse(endMs);
} catch (ParseException e) {
e.printStackTrace();
}
workDays = daysBetween(earlydate, latedate);
workHours = workDays * 24 + Integer.parseInt(endTimes[3]) - Integer.parseInt(startTimes[3]);
}
}else {//不同的年
String startMs = startTime.substring(0, 10);
String endMs = endTime.substring(0, 10);
Date earlydate = new Date();
Date latedate = new Date();
DateFormat df = DateFormat.getDateInstance();
try {
earlydate = df.parse(startMs);
latedate = df.parse(endMs);
} catch (ParseException e) {
e.printStackTrace();
}
workDays = differentDays(earlydate, latedate);
workHours = workDays * 24 + Integer.parseInt(endTimes[3]) - Integer.parseInt(startTimes[3]);
}
System.out.println();
System.out.println("------------------------------");
System.out.println(workDays);
System.out.println(workHours);
return workHours;
}其中用到的两个方法如下：
public static String[] getStrings(String time) {
String[] s = time.split("-");
return s;
}
public static final int daysBetween(Date early, Date late) {
java.util.Calendar calst = java.util.Calendar.getInstance();
java.util.Calendar caled = java.util.Calendar.getInstance();
calst.setTime(early);
caled.setTime(late);
// 设置时间为0时
calst.set(java.util.Calendar.HOUR_OF_DAY, 0);
calst.set(java.util.Calendar.MINUTE, 0);
calst.set(java.util.Calendar.SECOND, 0);
caled.set(java.util.Calendar.HOUR_OF_DAY, 0);
caled.set(java.util.Calendar.MINUTE, 0);
caled.set(java.util.Calendar.SECOND, 0);
// 得到两个日期相差的天数
int days = ((int) (caled.getTime().getTime() / 1000) - (int) (calst.getTime().getTime() / 1000)) / 3600 / 24;
return days;
}
public static int differentDays(Date date1, Date date2) {
Calendar calst = Calendar.getInstance();
calst.setTime(date1);
Calendar caled = Calendar.getInstance();
caled.setTime(date2);
int day1 = calst.get(Calendar.DAY_OF_YEAR);
int day2 = caled.get(Calendar.DAY_OF_YEAR);
int year1 = calst.get(Calendar.YEAR);
int year2 = caled.get(Calendar.YEAR);
calst.set(java.util.Calendar.HOUR_OF_DAY, 0);
calst.set(java.util.Calendar.MINUTE, 0);
calst.set(java.util.Calendar.SECOND, 0);
caled.set(java.util.Calendar.HOUR_OF_DAY, 0);
caled.set(java.util.Calendar.MINUTE, 0);
caled.set(java.util.Calendar.SECOND, 0);
if (year1 != year2) // 同一年
{
int timeDistance = 0;
for (int i = year1; i < year2; i++) {
if (i % 4 == 0 && i % 100 != 0 || i % 400 == 0) {// 闰年
timeDistance += 366;
} else {// 不是闰年
timeDistance += 365;
}
}
return timeDistance + (day2 - day1);
} else {// 不同年
System.out.println("判断day2 - day1 : " + (day2 - day1));
return day2 - day1;
}
}