1001. A+B Format (20)
2017-10-18 20:30
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1001. A+B Format (20)
时间限制400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input
Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.
Output
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input
-1000000 9
Sample Output
-999,991
提交代码
题目的坑点在:当不足三的倍数时从后面开始排,11000输出是11,000;很容易写成110,00;只要注意到了不足3的倍数个时是在哪里输出,应该
很快就可以通过。
#include<iostream> #include<cstring> #include<cstdio> #include<algorithm> using namespace std; int main(){ int a,b; int num[10]; int len; // freopen("input.txt","r",stdin); scanf("%d%d",&a,&b); a+=b; if(a==0){ printf("0\n"); return 0; } if(a<0){ a = -a; printf("-"); } while(a>0){ num[len++] = a%10; a /= 10; } int cnt = 0; for(int i = len-1;i>=0;i--){ cnt++; printf("%d",num[i]); if(abs(cnt - len%3)%3==0&&i != 0){ printf(","); } } printf("\n"); return 0; }
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