LeetCode 48 Rotate Image
2017-10-13 14:01
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原题:(频率2)
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note:
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Example 2:
题意:向右旋转90°
代码和思路:
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note:
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Given input matrix = [ [1,2,3], [4,5,6], [7,8,9] ], rotate the input matrix in-place such that it becomes: [ [7,4,1], [8,5,2], [9,6,3] ]
Example 2:
Given input matrix = [ [ 5, 1, 9,11], [ 2, 4, 8,10], [13, 3, 6, 7], [15,14,12,16] ], rotate the input matrix in-place such that it becomes: [ [15,13, 2, 5], [14, 3, 4, 1], [12, 6, 8, 9], [16, 7,10,11] ]
题意:向右旋转90°
代码和思路:
class Solution { public void rotate(int[][] matrix) { //先向左90度转,把横排转换为竖排 for(int i=0;i<matrix.length;i++){ for(int j = i;j<matrix[0].length;j++){ int temp = matrix[i][j]; matrix[i][j] = matrix[j][i]; matrix[j][i] = temp; } } //然后将竖排交换(第一竖排换最后竖排,第二换倒数第二) for(int i=0;i<matrix.length;i++){ for(int j = 0;j<matrix.length/2;j++){ int temp = matrix[i][j]; matrix[i][j] = matrix[i][matrix.length-1-j]; matrix[i][matrix.length-1-j] = temp; } } } }
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