您的位置:首页 > 其它

hihocoder 1445 : 后缀自动机二·重复旋律5(后缀自动机)

2017-10-10 19:39 399 查看
给入门新手的模板题,套kuangbin大佬的模板。

当前节点的minlen就等于当前节点的fa节点的maxlen+1。

#include <bits/stdc++.h>
using namespace std;
const int CHAR = 26;
const int MAXN = 1100010;
long long res = 0;
struct SAM_Node
{
SAM_Node *fa,*next[CHAR];
int len;
int id,pos;
SAM_Node() {}
SAM_Node(int _len)
{
fa = 0;
len = _len;
memset(next,0,sizeof(next));
}
};
SAM_Node SAM_node[MAXN*2], *SAM_root, *SAM_last;
int SAM_size;
SAM_Node *newSAM_Node(int len)
{
SAM_node[SAM_size] = SAM_Node(len);
SAM_node[SAM_size].id = SAM_size;
return &SAM_node[SAM_size++];
}
SAM_Node *newSAM_Node(SAM_Node *p)
{
SAM_node[SAM_size] = *p;
SAM_node[SAM_size].id = SAM_size;
return &SAM_node[SAM_size++];
}
void SAM_init()
{
SAM_size = 0;
SAM_root = SAM_last = newSAM_Node(0);
SAM_node[0].pos = 0;
}
void SAM_add(int x,int len)
{
SAM_Node *p = SAM_last, *np = newSAM_Node(p->len+1);
np->pos = len;
SAM_last = np;
for(; p && !p->next[x]; p = p->fa)
p->next[x] = np;
if(!p)
{
np->fa = SAM_root;
res += (np->len-np->fa->len);
return;
}
SAM_Node *q = p->next[x];
if(q->len == p->len + 1)
{
np->fa = q;
res += (np->len-np->fa->len);
return;
}
SAM_Node *nq = newSAM_Node(q);
nq->len = p->len + 1;
q->fa = nq;
np->fa = nq;
for(; p && p->next[x] == q; p = p->fa)
p->next[x] = nq;
res += (np->len-np->fa->len);
}
void SAM_build(char *s)
{
SAM_init();
int len = strlen(s);
for(int i = 0; i < len; i++)
SAM_add(s[i] - 'a',i+1);
}

char str[MAXN];

int main()
{
scanf("%s",str);
SAM_build(str);
printf("%lld\n",res);
return 0;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: