【hihocoder 1369】网络流一·Ford-Fulkerson算法

【Link】:http://hihocoder.com/problemset/problem/1369

【Description】

【Solution】

最大流模板题

【NumberOf WA】

【Reviw】

【Code】

#include <bits/stdc++.h>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define ms(x,y) memset(x,y,sizeof x)
#define ri(x) scanf("%d",&x)
#define rl(x) scanf("%lld",&x)
#define rs(x) scanf("%s",x+1)
#define oi(x) printf("%d",x)
#define ol(x) printf("%lld",x)
#define oc putchar(' ')
#define os(x) printf(x)
#define all(x) x.begin(),x.end()
#define Open() freopen("F:\\rush.txt","r",stdin)
#define Close() ios::sync_with_stdio(0)

typedef pair<int,int> pii;
typedef pair<LL,LL> pll;

const int dx[9] = {0,1,-1,0,0,-1,-1,1,1};
const int dy[9] = {0,0,0,-1,1,-1,1,-1,1};
const double pi = acos(-1.0);
const int N = 500;
const int INF = 0x3f3f3f3f;

int n,m,flow[N+10][N+10],pre[N+10];
queue <int> dl;

int main(){
//Open();
//Close();
ri(n),ri(m);
rep1(i,1,m){
int x,y,z;
ri(x),ri(y),ri(z);
flow[x][y]+=z;
}

int ans = 0;
while (1){
while (!dl.empty()) dl.pop();
ms(pre,255);
dl.push(1);
pre[1] = 0;
while (!dl.empty()){
int x = dl.front();
dl.pop();
for (int i = 1;i <= n;i++)
if (pre[i]==-1 && flow[x][i]){
pre[i] = x;
dl.push(i);
}
}
if (pre
==-1) break;
int mi = INF;
int now = n;
while (now != 1){
mi = min(mi,flow[pre[now]][now]);
now = pre[now];
}
now = n;
while (now != 1){
flow[pre[now]][now] -= mi;
now = pre[now];
}
ans += mi;
}
oi(ans);puts("");
return 0;
}