PAT 甲级 1058. A+B in Hogwarts (20)
2017-10-01 16:51
525 查看
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to
compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
Sample Output:
compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
#include <iostream> #include <vector> #include <algorithm> #include <cstring> #include <stack> #include <queue> #define lowbit(i) ((i)&(-i)) using namespace std; int main() { int g1, g2, s1, s2, k1, k2,g,s,k; scanf("%d.%d.%d %d.%d.%d", &g1, &s1, &k1, &g2, &s2, &k2); int carry = 0; k = (k1 + k2) % 29; if (k1 + k2 >= 29) carry = 1; s = (s1 + s2 + carry) % 17; if (s1 + s2 + carry >= 17) carry = 1; else carry = 0; g = g1 + g2 + carry; printf("%d.%d.%d\n", g, s, k); cin >> g; return 0; }
相关文章推荐
- PAT甲级1058. A+B in Hogwarts (20)
- PAT甲级真题及训练集(14)--1058. A+B in Hogwarts (20)
- 【PAT甲级】1058. A+B in Hogwarts (20)
- 1058. A+B in Hogwarts (20) PAT 甲级
- PAT - 甲级 - 1058. A+B in Hogwarts (20)(进制转换)
- pat甲级1058. A+B in Hogwarts (20)
- 1058. A+B in Hogwarts (20)-PAT甲级真题
- 浙江大学PAT_甲级_1058. A+B in Hogwarts (20)
- 【PAT】【Advanced Level】1058. A+B in Hogwarts (20)
- PAT 1058. A+B in Hogwarts (20)
- PAT-A-1058. A+B in Hogwarts (20)
- PAT (Advanced Level) Practise 1058 A+B in Hogwarts (20)
- 【PAT】A1058. A+B in Hogwarts (20)
- PAT程序设计考题——甲级1058(A+B in Hogwarts ) C++实现
- PAT甲题题解-1058. A+B in Hogwarts (20)-大水题
- 【PAT (Advanced Level)】1058. A+B in Hogwarts (20)
- 【c++】PAT(advanced level)1058. A+B in Hogwarts (20)
- PAT 1058. A+B in Hogwarts (20)(简单加法)(待修改)
- PAT-A 1058. A+B in Hogwarts (20)
- PAT---1058. A+B in Hogwarts (20)