【LeetCode】算法题 27 Remove Element
2017-09-29 16:10
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题目:Remove Element
Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't m
a1ca
atter what you leave beyond the new length.
Example:
Given input array nums =
Your function should return length = 2, with the first two elements of nums being 2
贴代码:
int removeElement(int* nums, int numsSize, int val) {
int i = 0;
int rest = 0;
for (i = 0; i < numsSize; i++) {
if (nums[i] != val) {
nums[rest] = nums[i];
rest++;
}
}
return rest;
}
Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't m
a1ca
atter what you leave beyond the new length.
Example:
Given input array nums =
[3,2,2,3], val =
3
Your function should return length = 2, with the first two elements of nums being 2
贴代码:
int removeElement(int* nums, int numsSize, int val) {
int i = 0;
int rest = 0;
for (i = 0; i < numsSize; i++) {
if (nums[i] != val) {
nums[rest] = nums[i];
rest++;
}
}
return rest;
}
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