您的位置:首页 > 其它

后缀数组模板

2017-09-27 22:12 127 查看
const int N = 1e6+10;
int n;

namespace SA {
int sa
, rank
, height
, s[N<<1], t[N<<1], p
, cnt
, cur
;
int MIN
[30];
#define pushS(x) sa[cur[s[x]]--] = x
#define pushL(x) sa[cur[s[x]]++] = x
#define inducedSort(v) fill_n(sa, n, -1); fill_n(cnt, m, 0);
for (int i = 0; i < n; i++) cnt[s[i]]++;
for (int i = 1; i < m; i++) cnt[i] += cnt[i-1];

for (int i = 0; i < m; i++) cur[i] = cnt[i]-1;

for (int i = 1; i < m; i++) cur[i] = cnt[i-1];

for (int i = 0; i < n; i++) if (sa[i] > 0 &&  t[sa[i]-1]) pushL(sa[i]-1);
for (int i = 0; i < m; i++) cur[i] = cnt[i]-1;

for (int i = n-1;  ~i; i--) if (sa[i] > 0 && !t[sa[i]-1]) pushS(sa[i]-1)
void sais(int n, int m, int *s, int *t, int *p) {
int n1 = t[n-1] = 0, ch = rank[0] = -1, *s1 = s+n;
for (int i = n-2; ~i; i--) t[i] = s[i] == s[i+1] ? t[i+1] : s[i] > s[i+1];
for (int i = 1; i < n; i++) rank[i] = t[i-1] && !t[i] ? (p[n1] = i, n1++) : -1;
inducedSort(p);
for (int i = 0, x, y; i < n; i++) if (~(x = rank[sa[i]])) {
if (ch < 1 || p[x+1] - p[x] != p[y+1] - p[y]) ch++;
else for (int j = p[x], k = p[y]; j <= p[x+1]; j++, k++)
if ((s[j]<<1|t[j]) != (s[k]<<1|t[k])) {ch++; break;}
s1[y = x] = ch;
}
if (ch+1 < n1) sais(n1, ch+1, s1, t+n, p+n1);
else for (int i = 0; i < n1; i++) sa[s1[i]] = i;
for (int i = 0; i < n1; i++) s1[i] = p[sa[i]];
inducedSort(s1);
}
template<typename T>
int mapCharToInt(int n, const T *str) {
int m = *max_element(str, str+n);
fill_n(rank, m+1, 0);
for (int i = 0; i < n; i++) rank[str[i]] = 1;
for (int i = 0; i < m; i++) rank[i+1] += rank[i];
for (int i = 0; i < n; i++) s[i] = rank[str[i]] - 1;
return rank[m];
}
template<typename T>
void suffixArray(int n, const T *str) {
int m = mapCharToInt(++n, str);
sais(n, m, s, t, p);
for (int i = 0; i < n; i++) rank[sa[i]] = i;
for (int i = 0, h = height[0] = 0; i < n-1; i++) {
int j = sa[rank[i]-1];
while (i+h < n && j+h < n && s[i+h] == s[j+h]) h++;
if (height[rank[i]] = h) h--;
}
}
void RMQ_init(){
for(int i=0; i<n; i++) MIN[i][0] = height[i+1];
for(int j=1; (1<<j)<=n; j++){
for(int i=0; i+(1<<j)<=n; i++){
MIN[i][j] = min(MIN[i][j-1], MIN[i+(1<<(j-1))][j-1]);
}
}
}
int RMQ(int L, int R){
int k = 0;
while((1<<(k+1)) <= R-L+1) k++;
return min(MIN[L][k], MIN[R-(1<<k)+1][k]);
}
int LCP(int i, int j){
if(rank[i] > rank[j]) swap(i, j);
return RMQ(rank[i], rank[j]-1);
}
void init(char *str){
str
= 0;
suffixArray(n, str);
RMQ_init();
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: